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Alexus [3.1K]
4 years ago
12

0.102 g of an unknown(non electrolyte) compound is dissolved in enough water to make 100. mL of a solution and has an osmotic pr

essure of 28.1 mmHg at 20C. Calculate the molar mass of the compound.
Chemistry
1 answer:
Leni [432]4 years ago
4 0

Answer:

680 g/m is the molar mass for the unknown, non electrolyte, compound.

Explanation:

Let's apply the formula for osmotic pressure

π = Molarity . R . T

T = T° absolute (in K)

R = Universal constant gases

π = Pressure

Molarity = mol/L

As units of R are  L.atm/mol.K, we have to convert the mmHg to atm

760 mmHg  is 1 atm

28.1 mmHg is (28.1  .1)/760 = 0.0369 atm

0.0369 atm = M . 0.082 L.atm/mol.K . 293K

(0.0369 atm / 0.082 mol.K/L.atm . 293K) = M

0.0015 mol/L = Molarity

This data means the mol of solute in 1L, but we have 100mL so

Molarity . volume = mol

0.0015 mol/L . 0.1L = 1.5x10⁻⁴ mole

The molar mass will be: 0.102g / 1.5x10⁻⁴ m = 680 g/m

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\huge\pink{Answer}

0.0006 in scientific notation is 6 × 10-4

<h2>Step by step Explanation:</h2>

All numbers in scientific notation or standard form are written in the form

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To convert 0.0006 into scientific notation, follow these steps:

Move the decimal 4 times to right in the number so that the resulting number, m = 6, is greater than or equal to 1 but less than 10

Since we moved the decimal to the right the exponent n is negative

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4 years ago
Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4g of magnesium and excess cop
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Answer:

The answer to your question is 280 g of Mg(NO₃)₂

Explanation:

Data

Efficiency = 30.80 %

Mg(NO₃)₂ = ?

Magnesium = 147.4 g

Copper (II) nitrate = excess

Balanced Reaction

                     Mg  +   Cu(NO₃)₂    ⇒    Mg(NO₃)₂   +   Cu

                  Reactants           Elements            Products

                         1                          Mg                     1

                         1                          Cu                      1

                         2                          N                       2

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Process

1.- Calculate the theoretical yield

Molecular weight Mg = 24

Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)

                                              = 24 + 28 + 96

                                              = 148 g

                           24 g of Mg  --------------------  148 g of Mg(NO₃)₂

                          147.4 g of Mg -------------------   x

                            x = (147.4 x 148) / 24

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2.- Calculate the Actual yield

yield percent = \frac{actual yield}{theoretical yield}

Solve for actual yield

Actual yield = Yield percent x Theoretical yield

Substitution

Actual yield = \frac{30.8}{100} x 908.96

Actual yield = 279.95 ≈ 280g

                     

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