Choice A is something we'll come back to
Choice B is false because the line does not go uphill as we move from left to right. The graphed line has a negative slope, which contradicts what choice B is saying.
Choice C is false for similar reasons as choice B. The slope should be negative.
Choice D has a negative slope, but the y intercept is wrong. The y intercept should be 3. So choice D is false as well.

We've eliminated choices B through D.

Choice A must be the answer through process of elimination.

------------

Here's an alternative method:

If we started at a point like (0,3) and move to (4,0), note how the slope is -3/4

This is because we've moved down 3 units and to the right 4 units.

m = slope = rise/run = -3/4

We can also use the slope formula m = (y2-y1)/(x2-x1) to see this.

Then we pick on a point that is on the diagonal line. It could be any point really, but the point your teacher used for choice A is (x1,y1) = (-4,6)

So,

y - y1 = m(x - x1)

y - 6 = (-3/4)(x - (-4))

y - 6 = (-3/4)(x + 4)

y = (-3/4)(x + 4) + 6

7 0

3 years ago

Lesechka [4]

The answer would be 500

4 0

3 years ago

Strike441 [17]

Answer:

i). x³ + 9x² + yz - 15

ii). -21m³np - 8p⁵q + mnp + 4mn + 100

Step-by-step explanation:

Question (38)

i). Two expressions are -5x² - 4yz + 15 and x³+ 4x²- 3yz

By subtracting expression (1) from expression (2) we can the expression by addition which we can get expression (1).

(x³+ 4x²- 3yz) - (-5x² - 4yz + 15) = x³ + 4x² - 3yz + 5x² + 4yz - 15

= x³ + 9x² + yz - 15

ii). -15m³np + 2p⁵q - 6m³pn + mnp + 4mn - 10qp⁵+ 100

= (-15m³np - 6m³np) + (2p⁵q - 10qp⁵) + mnp + 4mn + 100

= -21m³np - 8p⁵q + mnp + 4mn + 100

4 0

3 years ago