Find the product of (x + 9i)^2 Find the product of (x+(3+5i))^2

1 answer:

3 0

Remember that
$i = \sqrt{1}$
so
${i}^{2} = - 1 \: \: and \: \: {i}^{3} = - i \: \: \: and \: \: {i}^{4} = 1$
(a+ b)^2 = a^2 + 2ab + b^2

1. x^2 + 2x*9i + (9i)^2 = x^2 + 18xi - 81

2. x^2 + 2x*(3+5i)+ (3+5i)^2 = x^2 + 6x + 10xi+ 9+30i-25 = x^2 - 16 + 30i + 6x + 10xi

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Don't get this question

solniwko [45]

Answer:

17 and 18

Step-by-step explanation:

Writing every 2 digit number gives us :

10-99 including 10 and 99

For the first one we are looking for numbers where the number 3 appears only once so 33 would be invalid.

13,23,30,31,32,34,35,36,37,38,39,43,53,63,73,83,93

There are 17 2-digit numbers that have 3 exactly once

For the second one we are looking for number where the number 3 appears a minimum of once so 33 would be valid :

13,23,30,31,32,33,34,35,36,37,38,39,43,53,63,73,83,93

There are 18 2-digit numbers that have 3 at least once

Hope this helped and have a good day

5 0

2 years ago

the length of a rectangle is 9 centimeters more than the width. the area is 112 square centimeters. find the length and width of

NeX [460]

Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)

8 0

3 years ago

Read 2 more answers

Reduce to simplest form. 11) 3 - A) C) - C) D) 10 10 10

marshall27 [118]

Can you rewrite your question?

8 0

3 years ago

Can you all help me pls. Thanks.

Nataliya [291]

Answer:

Step-by-step explanation: