Answer: a) r= 4.82 * 10^-4 m ; b) 1420 V
Explanation: In order to solve this problem we have to take into account that potential for a sphere respec to V=0 at the infinity, which is given by:
V=k*Q/r where r is the radius of the drop
then we have
r=k*Q/V=9*10^9*38pC/710V= 4.82 * 10^-4 m
Finally if we join two drop to form one with the same radius but with twice charge the resultant potential is:
V= k*2*Q/(r)= 710*2= 1420 V
100J/20s= 5 joules per second
Or 5 watts
Answer:
C. tiny particles called charges flowing through the wires.
Explanation:
<h3> Hello!</h3>
An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space. It is measured as the net rate of flow of electric charge through a surface or into a control volume.
Hope it helps!
Refer to the diagram shown below.
The angle is in quadrant 4, therefore cos θ is positive.
The length of the hypotenuse is determined from the Pythagorean theorem as
c² = 3² + 4² = 25
c = 5
Calculate cosine of the reference angle.
cos θ = 3/5
Answer: 3/5
Answer:d
Explanation:
Given systems are state of matter and do not contain any heat instead Heat is required to change Phase or raise the temperature of the particular system.
For example 600 kg of ice at
Heat Required to convert it to water at is
Where L=latent heat of Fusion