Explanation:
Speed or velocity (V) = 35 m/s
Kinetic energy (K. E) = 1500 Joule
mass (m) = ?
We know
K.E = 1/2 * m * v²
1500 = 1/2 * m * 35²
1500 * 2 = 1225m
m = 3000 / 1225
m = 2.45 kg
The mass of the object is 2.45 kg
Hope it will help :)
Answer:
I'm not sure if I know whatever the answer is
The force that prevents motion when the surfaces of two objects come into contact is known as friction. Friction decreases a machine's mechanical advantage, or, to put it another way, reduces the output to input ratio.
<h3>How can I figure out the frictional force?</h3>
The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value.
The formula fr = Fr/N serves as a representation of it.
Therefore, 100N of force is needed to move an item with a mass of 50 kg.
It will accelerate by 10 m/s2.
If a substance's mass does not change over time, friction cannot affect it. Instead, friction can be affected in a variety of ways by an object's mass.
To Learn more About Friction, Refer:
brainly.com/question/24338873
#SPJ13
Explanation:
It is given that,
Mass of the woman, m₁ = 52 kg
Angular velocity, 
Mass of disk, m₂ = 118 kg
Radius of the disk, r = 3.9 m
The moment of inertia of woman which is standing at the rim of a large disk is :
I₁ = 790.92 kg-m²
The moment of inertia of of the disk about an axis through its center is given by :
I₂ =897.39 kg-m²
Total moment of inertia of the system is given by :
I = 1688.31 kg-m²
The angular momentum of the system is :
So, the total angular momentum of the system is 4980.5 kg-m²/s. Hence, this is the required solution.
Both are constants used in the definition of Forces (gravitational and electric,respectively)
Since those constants are proportional to the magnitude of the forces:
Having a small gravitational constant explains why there is no apparent force of attraction with objects of considerable low mass (they would need to have great value of mass for the equation to give an apreciable force)
Electrical interactions are usually strong, and thus require an appropiate constant to depict the phenomenon. We deal in this case with charges really small, but the forces are in different order of magnitude.
