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NNADVOKAT [17]
3 years ago
15

You drop a rock off a high cliff to the sea below. When the rock is several metres below you, you drop a second rock from the sa

me location. Before the rocks hit the sea, which of the following is true?
A) The separation (distance) between the rocks will decrease as they fall.

B) The separation (distance) between the rocks will stay the same as they fall.

C) The separation (distance) between the rocks will increase as they fall.

D)It's impossible to say anything about the distance between the rocks without more details.
Physics
1 answer:
aleksley [76]3 years ago
4 0

The statement “the separation (distance) between the rocks will stay the same as they fall” is TRUE. The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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Your go-cart breaks down right before the end of a race, so you have to push it over the finish line. The go-cart has a mass of
Flura [38]

a) W=mg=833 N by definition

b) F=ma=76.5 N according to Newton's second law

c) a=F/m=4.12 m/s^2

d) m=F/a=720/5.5=130.91 kg

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3 years ago
WILL GIVE YOU BRAINLIST IF YOU ANSWER
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Answer:

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Explanation:

willow ptarmigan

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The _of air resistance
Anettt [7]

Answer:

A)friction

Explanation:

The friction of air resistance slows down the acceleration due to gravity for real-world objects.

Air resistance is a form of friction found in atmosphere.

Frictional force is a force that opposes the motion of a body. It acts in the opposite direction of motion. Friction slows down real-world objects moving through the air.

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8 0
3 years ago
The voltage between the cathode and the screen of a television set is 22 kV. If we assume a speed of zero for an electron as it
il63 [147K]

Answer:

v= 8.8*10⁷ m/s

Explanation:

  • Assuming no friction present, the change in electrical potential energy, must be equal in magnitude, to the change in kinetic energy of the electron.
  • The change in the electrical potential energy, can be expressed as follows:

       \Delta U = (-e)*\Delta V

  • The change in kinetic energy, assuming that the electron started from rest, can be written as follows:

       \Delta K = \frac{1}{2} *m*v^{2}

       ⇒\Delta K = -\Delta U

  • From the equation above, replacing by ΔK and ΔU, we have:

       -\Delta U =- (-e)*\Delta V =\Delta K = \frac{1}{2} *m*v^{2}

  • Solving for v:

        v=\sqrt{\frac{2*e*\Delta V}{m_{e}} } =\sqrt{\frac{2*1.6e-19C*22e3V}{9.1e-31kg}} }\\ v= 8.8e7 m/s

4 0
3 years ago
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