Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Answer:
B at ordered pair 1, 2, hope this helped
Step-by-step explanation:
The property displayed here is the distributive property.
If you have a variable or unknown number inside or outside of parentheses, you can distribute it to each term and add the terms together, and it will remain true.
Example:
4(x + 5)
After distributing, it'll look like this:
4x + 20
Answer:−3K−395,−374,−198,−187
Step-by-step explanation:
Remove parentheses.
1−3K−396,0−374,0−198,0−187
Simplify 1-3K-3961−3K−396 to -3K-395−3K−395.
−3K−395,0−374,0−198,0−187
Simplify 0-3740−374 to -374−374.
−3K−395,−374,0−198,0−187
Simplify 0-1980−198 to -198−198.
−3K−395,−374,−198,0−187
Simplify 0-1870−187 to -187−187.
−3K−395,−374,−198,−187
You can add numbers mentally if there are zero's behind them.