Question

A piece of copper alloy with a mass of 85.0 g is heated from 30. °C to 45 °C. In the process, it absorbs 523 J of energy as heat. What is the specific heat of this copper alloy?
plz help me and answer this xx

Answer 1

Answer:

410.196 J/[kg*°C].

Explanation:

1) the equation of the energy is: E=c*m*(t₂-t₁), where E - energy (523 J), c - unknown specific heat of copper, m - mass of this copper [kg], t₂ - the final temperature, t₁ - initial temerature;

2) the specific heat of copper is:

$c=\frac{E}{m*(t_2-t_1)}; \ => \ c=\frac{523}{0.085*(45-30)}=\frac{523}{1.275}=410.196[\frac{J}{kg*C}].$