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prisoha [69]
3 years ago
9

This law brings Boyle's, Charle's, Avogadro's, and Gay-Lussac's laws together in one neat, easy to use package: PV = nRT. Using

simple algebra any of this variables can be isolated: P = nRT/V, V = nRT/P, T = PV/nR, n = PV/RT, or the ideal gas constant R computed. All gas calculations must be made using temperatures in Kelvin. If the ideal gas constant R = 0.08206 L∙atm/mol∙K, what volume will 1.00 mol of a gas occupy at 1.00 atm of pressure and 273 K?
Chemistry
1 answer:
NikAS [45]3 years ago
8 0

Answer:

22.4L

Explanation:

The following data were obtained from the question:

P = 1atm

T = 273K

n = 1mole

R = 0.08206 L∙atm/mol∙K

V =?

PV = nRT

V = nRT/P

V = (1 x 0.08206 x 273)/1

V = 22.4L

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As,
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                             Ksp  =  [Cu²⁺] [CO₃²⁻]
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