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sertanlavr [38]
3 years ago
13

Write 0.83+39 in standard form

Mathematics
2 answers:
SOVA2 [1]3 years ago
8 0
Are u dumb or somthing????????
hoa [83]3 years ago
3 0
39+0.83= 39.83

The answer is 39.83.

Hope this helps!
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Solve for a <br> -3= 5a/7+4/7
Nastasia [14]

Answer:

a = -5

Step-by-step explanation:

4 0
3 years ago
In January the students in a class red 72 books in February they read 56 books what is the approximate percentage decrease in th
snow_lady [41]

Answer: -12.5%

72 + 56 = 128

72 x / 128 x 100 = 56.25

56 / 128 x 100 = 43.75

43.75 - 56.25 = - 12.5

5 0
3 years ago
There are 158 students registered for American History classes. There are twice as many students registered in second period as
Margarita [4]

There are 28 students in first period and 56 students in sceond period and 74 students in third period

<em><u>Solution:</u></em>

Let the number of students in first period be "x"

Let the number of students in second period be "y"

Let the number of students in third period be "z"

<em><u>There are 158 students registered for American History classes.</u></em>

Therefore,

x + y + z = 158 ---------- eqn 1

<em><u>There are twice as many students registered in second period as first period</u></em>

number of students in second period = twice of number of students in first period

y = 2x ------- eqn 2

<em><u>There are 10 less than three times as many students in third period as in first period</u></em>

number of students in third period = 3 times number of students in first period - 10

z = 3x - 10 ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

x + 2x + 3x - 10 = 158

6x = 168

<h3>x = 28</h3>

<em><u>Substitute x = 28 in eqn 2</u></em>

y = 2(28)

<h3>y = 56</h3>

<em><u>Substitute x = 28 in eqn 3</u></em>

z = 3(28) - 10

z = 84 - 10

<h3>z = 74</h3>

Thus there are 28 students in first period and 56 students in sceond period and 74 students in third period

5 0
3 years ago
How can you find the area of an irregular polygon using area formulas?
algol [13]
Divide the polygon into separate shapes.  Like a rectangle and then a triangle.  
find the areas of those shapes and then add them together.

6 0
3 years ago
A fruit stand has to decide what to charge for their produce. They need $5.30 for 1 apple and 1 orange. They also need $7.30 for
Aneli [31]

Answer:

A fruit stand has to decide what to charge for their produce.

They need $ 5.30 for 1 apple and 1 orange.

They also need $ 7.30 for 1 apple and 2 oranges.

TO DETERMINE

To put this information into a system of linear equations.

TO find a unique price for an apple and an orange

EVALUATION

Let the price of an apple = x and price of an orange = y

So From the first condition that they need $ 5.30 for 1 apple and 1 orange we get

\sf{x + y = 5.30}x+y=5.30 - - - - Equation 1

Again from second condition that they need $ 7.30 for 1 apple and 2 oranges we get

\sf{x + 2y = 7.30}x+2y=7.30 - - - - Equation 2

So the required Set of linear equations are

x + y = 5.30

x + 2y = 7.30

Equation (2) - Equation (1) we get

y = 2

From Equation (1) we get

x = 5.30 - 2 = 3.30

Hence price of an apple = $ 3.30

The price of an orange = $ 2

7 0
2 years ago
Read 2 more answers
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