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sertanlavr [38]

4 years ago

13

Write 0.83+39 in standard form

2 answers:

SOVA2 [1]4 years ago

8 0

Are u dumb or somthing????????

hoa [83]4 years ago

3 0

39+0.83= 39.83

The answer is 39.83.

Hope this helps!

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Graph the function below:<br> y = 32 +1

sveta [45]

Slope: 0 | Y intercept 0, 33

7 0

3 years ago

A wheel on christine’s bicycle is 0.5 m in diameter christine races the bicycle for 50m how many times does the wheel turn as th

GarryVolchara [31]

Answer:

28.57

Step-by-step explanation:

3.14×0.5=1.750

50÷1.75=5000÷175 to eliminate the decimal points

5000÷175=28.571

then we round the answer to the nearest tenths

=28.57

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3 years ago

Find the x and y intercept of y=7×+5

Zina [86]

X-int. is (5/7,0)
y-int. is (0,5)

3 0

4 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago

(-5)x[-8)+1] solving bidmas

sp2606 [1]

I hope this helps you

(-5×-8)+1

40+1

41

8 0

3 years ago

Read 2 more answers