Answer:

Explanation:
Hello,
In this case, the undergoing chemical reaction is shown below:

Thus, we obtain 0.0471 g of lead (II) sulfate, the iodide ions in the original solution are computed below by stoichiometry, taking into account that into 1 mole of lead (II) iodide there are 2 moles of iodide ions:

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Because it may not contain Hydrogen or Oxygen
Answer:
1.5×10⁷ Hz
Explanation:
From the question given above, the following data were obtained:
Wavelength of radio wave (λ) = 20 m
Frequency (f) =?
Frequency and wavelength of a wave are related by the following equation:
v = λf
Where:
'v' is the velocity of electromagnetic wave.
'λ' is the wavelength
'f' is the frequency.
With the above formula, we can obtain the frequency of the radio wave as illustrated below:
Wavelength of radio wave (λ) = 20 m
Velocity (v) = 3×10⁸ m/s
Frequency (f) =?
v = λf
3×10⁸ = 20 × f
Divide both side by 20
f = 3×10⁸ / 20
f = 1.5×10⁷ Hz
Thus the frequency of the radio wave is 1.5×10⁷ Hz
Answer:
1. four in the first energy level, four in the second energy level
2. eight in the first energy level, zero in the second energy level
3. zero in the first energy level, eight in the second energy level
4. two in the first energy level, six in the second energy level *
Explanation:
1. four in the first energy level, four in the second energy level
2. eight in the first energy level, zero in the second energy level
3. zero in the first energy level, eight in the second energy level
4. two in the first energy level, six in the second energy level *
0.737 KL would be the answer, pls give brainliest.