Answer:
- Absorbance of sample solution = 1.21
- Absorbance of reagent blank = 0.205
Explanation:
In order to solve this problem we need to keep in mind the <em>Lambert-Beer law</em>, which states:
Where ε is the molar absorption coefficient, b is the length of the cuvette, and C is the concentration.
By looking at the equation above we can see that if ε and C are constant; and b is 5 times higher (5.00 cm vs 1.00 cm) then the absorbance will be 5 times higher as well:
- Absorbance of sample solution = 0.242 * 5 = 1.21
- Absorbance of reagent blank = 0.041 * 5 = 0.205
Answer : The value of 
of this reaction is, 
At equilibrium, [L-malate] > [oxaloacetate]
Explanation :
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = +30 kJ/mol = +30000 J/mol
R = gas constant = 8.314 J/K.mol
T = temperature = 
= equilibrium constant = ?
The given reaction is:
Therefore, the value of of this reaction is,
As, the value of < 1 that means the reaction mixture contains reactants.
At equilibrium, [L-malate] > [oxaloacetate]
Answer is: <span>mass of calcium carbonate needed is 120 grams.
</span>Chemical reaction:
CaCO₃(s) → CaO(s) + CO₂(g)<span>.
</span>V(CO₂) = 27.0 L.
Vm = 22.4 L/mol.
n(CO₂) = V(CO₂) ÷ Vm.
n(CO₂) = 27 L ÷ 22.4 L/mol.
n(CO₂) = 1.2 mol.
From chemical reaction: n(CO₂) : n(CaCO₃) = 1 : 1.
m(CaCO₃) = 1.2 mol.
m(CaCO₃) = n(CaCO₃) · M(CaCO₃).
m(CaCO₃) = 1.2 mol · 100 g/mol.
m(CaCO₃) = 120 g.
D but I’m not to sure about it
Answer : The mass of 
dissolved will be, 0.2365 grams
Explanation :
First we have to calculate the concentration of .
As we know that,
where,
= concentration of = ?
= partial pressure of = 1.65 atm
= Henry's law constant = 
Now put all the given values in the above formula, we get:
The concentration of = 
Now we have to calculate the moles of
Now we have to calculate the mass of
Therefore, the mass of dissolved will be, 0.2365 grams
