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stich3 [128]
3 years ago
14

A concentrated salt solution has a mass of 5.29 g for a 5.00 mL sample. What is the specific gravity of this solution

Chemistry
1 answer:
TiliK225 [7]3 years ago
7 0

Answer:

\rho_s=1.07g/cc^3

Explanation:

From the question we are told that:

Mass M=5.29g

Volume V=5.00mL=>5.0cc^3

Generally the equation for Specific Gravity momentum is mathematically given by

Specific\ Gravity\ g= Density\ of\ Salt\ Solution\ \rho_s / Density\ of\ Water\ \rho_w

 g=\frac{ \rho_s} { \rho_w}

 \rho_s=\frac{ g} { \rho_w}

 \rho_s=\frac{ 5.29} { 5}

 \rho_s=1.07g/cc^3

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Answer:

Explanation:

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The equilibrium of acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka: 4,75

Where <em>CH₃COOH </em>is the acid and <em>CH₃COO⁻ </em>is the conjugate base.

Thus, Henderson-Hasselbalch formula for acetic acid equilibrium is:

pH = 4,75 + log₁₀ \frac{[CH_{3}COO^-]}{[CH_{3}COOH]}

a) The pH is:

pH = 4,75 + log₁₀ \frac{[2 mol]}{[2 mol]}

<em>pH = 4,75</em>

<em></em>

b) The pH is:

pH = 4,75 + log₁₀ \frac{[2 mol]}{[1mol]}

<em>pH = 5,05</em>

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I hope it helps!

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3 years ago
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