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stich3 [128]
3 years ago
14

A concentrated salt solution has a mass of 5.29 g for a 5.00 mL sample. What is the specific gravity of this solution

Chemistry
1 answer:
TiliK225 [7]3 years ago
7 0

Answer:

\rho_s=1.07g/cc^3

Explanation:

From the question we are told that:

Mass M=5.29g

Volume V=5.00mL=>5.0cc^3

Generally the equation for Specific Gravity momentum is mathematically given by

Specific\ Gravity\ g= Density\ of\ Salt\ Solution\ \rho_s / Density\ of\ Water\ \rho_w

 g=\frac{ \rho_s} { \rho_w}

 \rho_s=\frac{ g} { \rho_w}

 \rho_s=\frac{ 5.29} { 5}

 \rho_s=1.07g/cc^3

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Answer:

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14. What is the pH of a 0.24 M solution of sodium propionate, NaC3H502, at 25°C? (For
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Answer:

9.1

Explanation:

Step 1: Calculate the basic dissociation constant of propionate ion (Kb)

Sodium propionate is a strong electrolyte that dissociates according to the following equation.

NaC₃H₅O₂ ⇒ Na⁺ + C₃H₅O₂⁻

Propionate is the conjugate base of propionic acid according to the following equation.

C₃H₅O₂⁻ + H₂O ⇄ HC₃H₅O₂ + OH⁻

We can calculate Kb for propionate using the following expression.

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Step 2: Calculate the concentration of OH⁻

The concentration of the base (Cb) is 0.24 M. We can calculate [OH⁻] using the following expression.

[OH⁻] = √(Kb × Cb) = √(7.7 × 10⁻¹⁰ × 0.24) = 1.4 × 10⁻⁵ M

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We will use the following expression.

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[H⁺] = Kw/[OH⁻] = 1.0 × 10⁻¹⁴/1.4 × 10⁻⁵ = 7.1 × 10⁻¹⁰ M

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We will use the definition of pH.

pH = -log [H⁺] = -log 7.1 × 10⁻¹⁰ = 9.1

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