Answer:
A. Density of object = 0.86 g/mL
B. The object will float in the water.
Explanation:
The following data were obtained from the question:
Volume of water = 6.2 mL
Mass (m) of object = 1.2 g
Volume of water + Object = 7.59 mL
Density of object =?
Density of water = 1 g/mL
Next, we shall determine the volume of the object. This can be obtained as follow:
Volume of water = 6.2 mL
Volume of water + Object = 7.59 mL
Volume of object =?
Volume of object = (Volume of water + Object) – (Volume of water)
Volume of object = 7.59 – 6.2
Volume of object = 1.39 mL
Therefore, the volume of the object is 1.39 mL
A. Determination of the density of the object.
Mass (m) of object = 1.2 g
Volume (V) of object = 1.39 mL
Density (D) of object =?
Density = mass /volume
Density = 1.2/1.39
Density of object = 0.86 g/mL
B. Determination of whether the object will float or sink.
Density of object = 0.86 g/mL
Density of water = 1 g/mL
From the above, we can see that the density of water is greater than that of the object. This implies that the object is lighter than water. Therefore, the object will float in the water.
for pure water.
at 25 °C.