Question

ViT2 = V2T, V = V2

Answer 1

Answer:

V₂ = 285 mL

Explanation:

Given data:

Initial volume of bag = 250 mL

Initial temperature = 19.0°C

Final temperature = 60.0°C

Final volume = ?

Solution:

The given problem will be solved by using Charles Law,

This law stated that " The volume of given amount of gas at constant pressure and constant number of moles is directly proportional to its temperature"

Mathematical relationship:

V₁/T₁  = V₂/T₂

Now we will convert the temperature into kelvin.

Initial temperature = 19.0 + 273 = 292K

Final temperature = 60.0 + 273 = 333K

Now we will put the values in formula:

V₁/T₁  = V₂/T₂

250 mL / 292K  =  V₂/ 333K

0.856 mL /K = V₂/ 333K

V₂ = 0.86×333K. mL /K

V₂ = 285 mL