Answer:
Reaction 1 is balanced but 2 is not balanced , the balance equation are :
1. ![CH_{3}COOH(aq) + NaHCO_{3}(aq)\rightarrow CO_{2}(g) + H_{2}O(l) + CH_{3}COONa(aq)](https://tex.z-dn.net/?f=CH_%7B3%7DCOOH%28aq%29%20%2B%20NaHCO_%7B3%7D%28aq%29%5Crightarrow%20CO_%7B2%7D%28g%29%20%2B%20H_%7B2%7DO%28l%29%20%2B%20CH_%7B3%7DCOONa%28aq%29)
2.![CaCl_{2}(aq) + 2NaHCO_{3}(aq)\rightarrow CaCO_{3}(aq) + H_{2}O(l) + 2NaCl(aq) + H_{2}O(aq)](https://tex.z-dn.net/?f=CaCl_%7B2%7D%28aq%29%20%2B%202NaHCO_%7B3%7D%28aq%29%5Crightarrow%20CaCO_%7B3%7D%28aq%29%20%2B%20H_%7B2%7DO%28l%29%20%2B%202NaCl%28aq%29%20%2B%20H_%7B2%7DO%28aq%29)
Explanation:
Balanced Equations : These are the equation which follows the law of conservation of mass .
The total number of atoms present in reactant is equal to total number of atoms present in product.
1. ![CH_{3}COOH(aq) + NaHCO_{3}(aq)\rightarrow CO_{2}(g) + H_{2}O(l) + CH_{3}COONa(aq)](https://tex.z-dn.net/?f=CH_%7B3%7DCOOH%28aq%29%20%2B%20NaHCO_%7B3%7D%28aq%29%5Crightarrow%20CO_%7B2%7D%28g%29%20%2B%20H_%7B2%7DO%28l%29%20%2B%20CH_%7B3%7DCOONa%28aq%29)
This is acid - base type reaction where
act as Acid
act as weak base
Reactant :
,![NaHCO_{3}](https://tex.z-dn.net/?f=NaHCO_%7B3%7D)
Number of atoms of :
C = 2 (
) + 1 (
)
= 2 + 1
= 3
H = 4(
) + 1 (
)
= 4 + 1
5
O = 2(
) + 3 (
)
= 5
Na = 1 (
)
= 1
Product :
,
, ![CH_{3}COONa(aq)](https://tex.z-dn.net/?f=CH_%7B3%7DCOONa%28aq%29)
Number of atoms :
C = 1(
) + 2(
)
= 1 + 2
= 3
H = 2(
) + 3(
)
= 2 + 3
= 5
O = 1(
) + 2(
)
+2(![CO_{2}(g)](https://tex.z-dn.net/?f=CO_%7B2%7D%28g%29)
= 1 + 2 + 2
= 5
Na = 1(![CH_{3}COONa(aq)](https://tex.z-dn.net/?f=CH_%7B3%7DCOONa%28aq%29)
= 1
Number of Na =1 , C = 3 , H= 5 and O =5 in both reactant and product , so it is a balanced reaction
2.
This is double displacement reaction .
Check the balancing in both reactant and products should be :
Na = 2
H = 2
Ca = 1
C = 2
O = 6
Cl = 2
Answer:
0.479 M or mol/L
Explanation:
So Molarity is moles/litres of solution...often written as M=mol/L
So here we are given grams of BaCl2 which we have to convert to moles. To convert to moles of BaCl2 we have to divide 63.2 g BaCl2 by molar mass of BaCl2 which is 208.23 g/mol so you get 63.2/208.23 = 0.3035 moles of BaCl2
Second step is converting the 634mL to litres by simply dividing by 1000 because we know 1 litre has 1000ml so 634/1000 = 0.634L
Now we just plug these guys in our molarity formula M=mol/L
M= 0.3035/0.634 = 0.479 M or mol/L
Answer:
<u>A baseball speeds up as it falls through the air.</u>
<u>A bumper car hit by another car moves off at an angle.</u>
<u>A balloon flies across the room when the air is released.</u>
Explanation:
<em>Let me know if you need any other help</em>
<em />
Answer:
c. 2,2-dichloropentane.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to firstly draw the structure of the reactant, pent-1-yne:
![CH\equiv C-CH_2-CH_2-CH_2](https://tex.z-dn.net/?f=CH%5Cequiv%20C-CH_2-CH_2-CH_2)
Now, we infer the halogen is added to the carbon atom with the most carbon atoms next to it, in this case, carbon #2, in order to write the following product:
![CH\equiv C-CH_2-CH_2-CH_2+2HCl\rightarrow CH_3- CCl_2-CH_2-CH_2-CH_2](https://tex.z-dn.net/?f=CH%5Cequiv%20C-CH_2-CH_2-CH_2%2B2HCl%5Crightarrow%20CH_3-%20CCl_2-CH_2-CH_2-CH_2)
Whose name is 2,2-dichloropentane.
Regards!
The answer is: H₃PO₄.
A phosphoric acid is three protic acid, which means that in water release tree protons.
Phosphoric acid ionizes in three steps in water.
First step: H₃PO₄(aq) ⇄ H₂PO₄⁻(aq) + H⁺(aq).
Second step: H₂PO₄⁻(aq)⇄ HPO₄²⁻(aq) + H⁺(aq).
Third step: HPO₄²⁻(aq) ⇄ PO₄³⁻(aq) + H⁺(aq).
Species that are present: H₃PO₄, H₂PO₄⁻, HPO₄²⁻, PO₄³⁻ and H⁺.
A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H⁺ in a solution.
Buffer is a solution that can resist pH change upon the addition of an acidic or basic components and it is able to neutralize small amounts of added acid or base, pH of the solution is relatively stable.