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Kisachek [45]
3 years ago
11

Chlorine monoxide accumulates in the stratosphere above Antarctica each winter and plays a key role in the formation of the ozon

e hole above the South Pole each spring. Eventually, ClO decomposes according to the equation:
Chemistry
1 answer:
Ahat [919]3 years ago
7 0

The question is incomplete, the complete question is;

Chlorine monoxide accumulates in the stratosphere above Antarctica each winter 3nd plays a key role the formation of the ozone hole above the South Pole each spring Eventually. CIO decomposes acco to the equation: 2CIO(g) rightarrow CL2(g) + O2(g) The second-order rate constant for the decomposition of CIO is 6950000000 M-1 s-1 at a particular temperature Determine the half-life of CIO when its initial concentration is .0000000185 M

Answer:

7.8 * 10^-3 s

Explanation:

Given that the half life of a second order reaction is obtained from the formula;

t1/2 = k-1[A]o-1

t1/2 = 1/k[A]o

second order rate constant (k) = 6950000000 M-1 s-1

initial concentration ([A]o) =0.0000000185 M

t1/2 = 1/6950000000 * 0.0000000185

t1/2 = 7.8 * 10^-3 s

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(3.88 x 10to the 26th)atoms of copper would be equal to how many moles of copper?
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What are 2 of the characteristics of temporary physical change
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2 years ago
Read 2 more answers
Can anybody check my answer?
anzhelika [568]

Answer:

\boxed{\text{25. 20 L; 26. 49 K}}

Explanation:

25. Boyle's Law

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p_{1}V_{1} = p_{2}V_{2}

Data:

\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}

Calculations:

\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}

26. Ideal Gas Law

We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.

pV = nRT

Data:  

p = 101.3 kPa

V = 20 L

n = 5 mol

R = 8.314 kPa·L·K⁻¹mol⁻¹

Calculation:

101.3 × 20 = 5 ×  8.314 × T

2026 = 41.57T

T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}

6 0
3 years ago
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