This should be correct, but it is not a 100% guarantee on my part.
Answer:
When HIV infects a cell, it first attaches to and fuses with the host cell. Then the virus uses the host cell's machinery to convert the viral RNA into DNA and replicate itself. The new copies of HIV then leave the host cell and move on to infect other cells.
Explanation:
In the majority of cases, the extra copy of chromosome 21 comes from the mother in the egg.
In a small percentage (less than 5%) of cases, the extra copy of chromosome 21 comes from the father through the sperm.
In the remaining cases, the error occurs after fertilization, as the embryo grows.
Histone deacetylase is responsible for removing the acetyl group from the histone 3 lysine 9 residue. Remember that deacetylation is one step in converting euchromatin to heterochromatin. Because euchromatin is transcriptionally active (transcriptional machinery is able to reach gene of interest), and blocking histone deacetylase activity would result in an the DNA remaining as euchromatin, we would expect to see an increase in transcriptional activity.
So there’s your answer: An increase in transcriptional activity.
They form a complex called chromatin