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alexandr1967 [171]
3 years ago
6

PLEASE MATH HELP DESPERATE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! WILL DO ANYTHING PLEASE. WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
sasho [114]3 years ago
7 0
The midpoint is the average of the endpoint coords.
If (x,y) is F, then -6=(-14+x)/2 and 7=(13+y)/2.
-14+x=-12 so x=2, and 14=13+y, so y=1 and F is (2,1).
so the answer is (2,1)
Naddika [18.5K]3 years ago
4 0
The distance between the y coordinates  of points D and M =   13-7 = 6 units
 and distance between x coordinates = 14-6 = 8

so x coordinate of the point F =  -6 + 8 = 2
and y  ................................F =  7 - 6 = 1

coordinates of point F  are (2,1)




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8(5x–3)–11(3x+7)=102
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40x - 24 - 33x - 77 = 102
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3 years ago
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Help!!! Quick!!! Plzzzzz!!!
max2010maxim [7]

Answer:

x = -8

y = 9

Step-by-step explanation:

to solve this expression using simultaneous equation, we would say let

y =9............................................. equation 1

 6x + 5y =-3............................................equation 2

substitute equation 1 into equation 2

-3 = 6x + 5y............................................equation 2

6x + 5(9) = -3

6x + 45 = -3

collect the like terms

6x = -3-45

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divide both sides by the coefficient of x which is 6

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x = -8

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3 years ago
Carpenters refer to the slope of a roof as the pitch on the roof
sweet [91]

Answer:

Step-by-step explanation:

pitch=4/12=1/3

4 0
2 years ago
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7 0
3 years ago
Assume the upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.2 centimeters (
MAVERICK [17]

Answer:

The interval [32.6 cm, 45.8 cm]

Step-by-step explanation:

According with the <em>68–95–99.7 rule for the Normal distribution:</em>  If \large \bar x  is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval

\large [\bar x - s, \bar x +s]

around 95% of the data must fall in the interval

\large [\bar x -2s, \bar x +2s] 

around 99.7% of the data must fall in the interval

\large [\bar x -3s, \bar x +3s]

So, the range of lengths that covers almost all the data (99.7%) is the interval

[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]

<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>

3 0
3 years ago
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