Given:
f1 = 20 Hz
f2 = 20000 Hz
speed of sound at 20 degrees celcius = 343 m/s
Solution:
for f1 = 20 Hz,
Using the equation:
lambda = speed of sound / f1 = 343 / 20 = 17.15 m
For f2:
lambda = speed of sound / f2 = 343 / 20000 = 0.01775 m
Therefore the wavelength range of audible sound in air would be 17.15 m to 0.01775 m.
Answer:
x(t) = ⅟₁₀₈t⁴ + 10t + 24
v(t) = ⅟₂₇t³ + 10
Explanation:
a(t) = C₁t²
velocity is the integral of acceleration
v(t) = ⅓C₁t³ + C₂
position is the integral of velocity
x(t) = (⅟₁₂C₁)t⁴ + C₂t + C₃
x(0) = 24 = (⅟₁₂C₁)0⁴ + C₂0 + C₃
C₃ = 24
x(6) = 96 = (⅟₁₂C₁)6⁴ + C₂6 + 24
72 = 108C₁ + 6C₂
C₂ = 12 - 18C₁
v(6) = 18 = ⅓C₁6³ + C₂
18 = 72C₁ + C₂
18 = 72C₁ + (12 - 18C₁)
6 = 54C₁
C₁ = 1/9
C₂ = 12 - 18(1/9)
C₂ = 10
Answer:
The product of the mass and the volume is known as momentum.
According to the law of momentum, it is stated that the two or more bodies remain in a constant state unless an external force is applied in an isolated room.
Momentum depends on the following:-
Mass
Velocity
Momentum = MASS \ X \ VOLUMEMomentum=MASS X VOLUME
\begin{gathered}momentum = 3000kgm/s\\\\mass = 2000kg\\\\velocity =\frac{momentum}{mass}\\\\v= \frac{3000}{2000} \\\\v= 1.5m/s\end{gathered}
momentum=3000kgm/s
mass=2000kg
velocity=
mass
momentum
v=
2000
3000
v=1.5m/s
Answer: Vibrating
Explanation:
Sound is produced when an object vibrates. The sound vibrations cause waves of pressure that travel through a medium, such as air, water, wood or metal. Sound is a form of mechanical energy.
