。and 。 are needed to describe a force

The air pressure inside a car tire is

Valentin [98]

Answer:

0.137m²

Explanation:

Pressure = Force/Area

Given

Force = 41,500N

Pressure = 3.00atm

since 1atm = 101325.00 N/m²

3atm = 3(101325.00)

3atm = 303,975N/m²

Pressure = 303,975N/m²

Get the area

Area = Force/Pressure

Area = 41500/303,975

Area = 0.137m²'

Hence the surface area of the inside of the tire is 0.137m²

7 0

3 years ago

List three measurements with different units this are equal to 5 meters

olganol [36]

5kg
50cm
500in
Hope this helped good luck to you

6 0

3 years ago

Xavier is administering medication to his patient. He administers four cups 4 points

Galina-37 [17]

Answer:

11 ounces

Explanation:

The patient gets 11 ounces of liquid.

From the description of this problem:

Xavier administers four cups of liquid each containing two ounces

The number of ounces in the four cups = 2 x 4 = 8ounces

Also,

One cup of the liquid contains 3 ounces.

Total number of ounces administered = 8 + 3 = 11 ounces.

6 0

2 years ago

A uniform steel girder of weight 22KN and of length 12m is lifted off the ground at one end by means of a crane. When the raised

Keith_Richards [23]

Answer:

Explanation:

For free body diagram see attached sheet .

W is weight of steel girder acting at the middle point of its length . T is tension in the cable .

OB = √ ( 12² - 2² )

= 11.83 m .

OC = 11.83 / 2 = 5.915 m

Taking moment of tension T and weight W about point O

W x OC = T x OB

22 x 5.915 = T x 11.83

T = 22 x 5.915 / 11.83

= 11 kN

Considering forces acting in vertical direction and equating forces in opposite direction

T + R = W

R = W - T

= 22 - 11 = 11 KN

So force of grinder on the ground = R

= 11 KN.

8 0

2 years ago

A piston–cylinder device initially contains 0.22 kg of steam at 200 kPa and 300°C. Now, the steam is cooled at constant pressure

wel

Explanation:

Defining compressibility factor (Z), which is also known as the gas deviation factor, is a correction factor which describes the deviation of a real gas from ideal gas behaviour.

Z = p/(density * Rs *T)

Where Rs is specific gas constant =R/M

Deriving the volume values from steam tables,

At 200kPa and 300°C, V1 = 1.31623 m3/kg

At 200kPa and 150°C, V2 = 0.95986 m3/kg

Change in volume, DV = m(V1 - V2)

= 0.2*(1.31623 - 0.95986)

= 0.07128 m3/kg

Also from steam tables,

The critical pressure, Pc = 22.06MPa

The critical temperature, Tc = 647.1K

Remember, gas constant, R = 0.4615 kPa.m3/kg.K

Therefore, reduced temperature at initial state, Tr = T1/Tc

= (360 + 273)/647.1

= 0.886

Also, reduced pressure at initial state, Pr = P1/Pr

= 200 x 10^-3/22.06

= 0.0091

But compressibility factor at initial state, Z1 = 0.9956

Ideal volume, Vi = m*R*T/P1

= (0.2*0.4615*(300+273))/200

= 0.2644m3

Compressibility volume, Vc = Z1*Vi

= 0.9956* 0.2644

= 0.2633m3

Reduced temperature at final state, Tr = T2/Tc

= (150+273)/647.1

= 0.65

Reduced pressure at final state, Pr = P2/Pc

= 200 x 10^-3/22.06

= 0.0091

Compressibility factor at final state, Z2 = 0.9897

3 0

3 years ago