Answer:
The electric field is 
Explanation:
Given that,
Radius = 0.357 m
Charge 
Point charge 
Distance = 0.815 m
We need to calculate the total electric field
Using formula of electric field

Where, q = point charge
r = distance
Put the value into the formula


Hence, The electric field is 
Complete Question
The complete question shown on the first uploaded image
Answer:
a)
The force on Q due to dipole is Attractive
b)
The charge Q exerts attractive force on the dipole
c)
Yes from the above parts, force depends on the sign of charge
d)
![F = kQq[\frac{d^{2}+2rd}{r^{2}(d+r)^{2}} ]](https://tex.z-dn.net/?f=F%20%3D%20kQq%5B%5Cfrac%7Bd%5E%7B2%7D%2B2rd%7D%7Br%5E%7B2%7D%28d%2Br%29%5E%7B2%7D%7D%20%5D)
e)
The magnitude o force decrease by a factor of 8.0 times
Explanation:
The explanation is shown on the second uploaded image
Answer:
36.408cm3
Explanation:
Since we acknowledge that density is d= m/v, once we switch it up to maintain v as the number to be found it will change to v=m/d. Therefore, 275.32/7.562 is 36.408 and the unit is cm cube!
Hope that helped!!
The formula for frequency is f = 1/T where f is frequency and T is period in seconds.
You have you period which is 0.008s and that is all you will need to solve or frequency in a wave:
f = 1/2
f = 1/0.008s
f = 125Hz
Answer:
<h2>
44 m/s</h2>
Explanation:
In this problem we are expected to calculate the velocity of Georges movements.
Given data
Total distance covered by George= 850+250= 1100 meters
Time taken by George to cover the total distance= 25 seconds
We know that velocity is, v= distance/ time
Therefore substituting our data into the expression for velocity we have
v= 1100/ 25= 44 m/s
Hence the velocity in m/s is 44