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zimovet [89]
3 years ago
8

Pasar 26 Segundos a Horas

Physics
1 answer:
ivolga24 [154]3 years ago
3 0

For this case we must convert 26 seconds to hours,

By definition we have to:

1 hour equals 3600 seconds.

So, if we propose a rule of three we have:

1 hour ----------> 3600 seconds

x ------------------> 26 seconds

Where the variable "x" represents the number of hours equivalent to 26 seconds:

x = \frac {26 * 1} {3600}\\x = 0.0072

Thus, 26 seconds equals approximately 0.0072 hours.

Answer:

0.0072 hours

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Answer:

i) The pressure acting on the base of <em>B</em> will be half the pressure acting on the base of <em>A</em>

ii) The pressure acting on the base of <em>B</em> will be the same as the pressure acting on the base of <em>A</em>

iii) The pressure on the base of drum <em>A</em> will be slightly less than the pressure on the base of drum <em>B</em>

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h_{max} = The height of the drums

ρ = The density of the liquid in the drum

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i) If <em>A</em> is completely filled, we have h_A = h_{max}

Therefore, P_A = h_{max}×\rho_{liquid}×g

If <em>B</em> is half filled, we have, h_B =  (1/2)·h_{max}

P_B = (1/2) × h_{max}×\rho_{liquid}×g

Therefore, P_B = (1/2) × P_A

The pressure acting on the base of <em>B</em> will be half the pressure acting on the base of <em>A</em>

ii) If both <em>A</em> and <em>B</em> are each filled with water (the same liquid), then the pressure on their bases will be P_A = h_{max}×\rho_{water}×g = P_B, the same, given that the acceleration due to gravity, <em>g</em>, is constant and the same in Nepal and India

iii) If <em>A</em> is filled with water, and <em>B</em> is filled with salty water, we have that, the density of salty water is slightly higher than water, therefore, we get;

P_A = h_{max}×\rho_{water}×g <  P_B =

The pressure on the base of drum <em>A</em> will be less than the pressure on the base of drum <em>B.</em>

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