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3 years ago

Pasar 26 Segundos a Horas

Physics

1 answer:

ivolga24 [154]3 years ago

3 0

For this case we must convert 26 seconds to hours,

By definition we have to:

1 hour equals 3600 seconds.

So, if we propose a rule of three we have:

1 hour ----------> 3600 seconds

x ------------------> 26 seconds

Where the variable "x" represents the number of hours equivalent to 26 seconds:

$x = \frac {26 * 1} {3600}\\x = 0.0072$

Thus, 26 seconds equals approximately 0.0072 hours.

Answer:

0.0072 hours

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Reto: Aníbal desea construir una carpa de base hexagonal de 1,40 m de altura. El vértice de la base es de 0,80m y la longitud de

Rudiy27

Answer:

1.- para cubrir la superficie lateral 4.32 metros²

2.- Area de la base 2.15 metros²

3.- Volumen 1 m³

4.- Area total 6.47 metros²

Explanation:

El área lateral sera calcular el area de seis triangulos iguales cuya base es

0.80 de base x 6 lados = 4.80 metros perimetro de la base

4.80 perimetro de base x 1.80 arista lateral / 2 = 4.32m2

Area de la base:

Perímetro x Apotema / 2

Siendo la Apotema la altura de los triangulos que componen un hexagono calculada utilizando el teorema de pitágoras:

$\sqrt{0.8^2 + (0.8/2)^2} = Apotema$

Apotema = 0.894427191

Area: 4.80 x 0.894427191 / 2 = 2.146625258

sumando el area de la base mas el area lateral se obtiene el area total

2.15 + 4.32 = 6.47 metros

Volumen de la pirámide:

Area de la Base x Altura / 3

2.15 x 1.40 / 3 = 1.00333 m3

3 0

3 years ago

What is the main source of energy

jolli1 [7]

Sun is the main source of energy

8 0

3 years ago

Read 2 more answers

Suppose we hang a heavy ball with a mass 13 kg (so the weight is ) from a steel wire 3.9 m long that is 3.1 mm in diameter (radi

Katena32 [7]

Answer:

1.635×10^-3m

Explanation:

Young modulus is the ratio of the tensile stress of a material to its tensile strain.

Young modulus = Tensile stress/tensile strain

Tensile stress = Force/Area

Given force = 130N

Area = Πr² = Π×(1.55×10^-3)²

Area = 4.87×10^-6m²

Tensile stress = 130/4.87×10^-6 = 8.39×10^7N/m²

Tensile strain = extension/original length

Tensile strain = e/3.9

Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²

2×10¹¹N/m² = 8.39×10^7/{e/3.9)}

2×10¹¹ = (8.39×10^7×3.9)/e

2×10¹¹e = 3.27×10^8

e = 3.27×10^8/2×10¹¹

e = 1.635×10^-3m

The stretch of the steel wire will be

1.635×10^-3m

7 0

3 years ago

The position-time equation for a cheetah chasing an antelope is:

pochemuha

Answer:

x = 1.6 + 1.7 t^2 omitting signs

a) at t = 0 x = 1.6 m

b) V = d x / d t = 3.4 t

at t = 0 V = 0

c) A = d^2 x / d t^2 = 3.4 (at t = 0 A = 3.4 m/s^2)

d) x = 1.6 + 1.7 * (4.4)^2 = 34.5 (position at 4.4 sec = 34.5 m)

4 0

2 years ago

by how many times occur in the force of attraction between two bodies change when the distance between then is reduced to one th

xenn [34]

Answer:

<em>The force is now 9 times the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrostatic force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Coulomb's formula is:

$\displaystyle F=k\frac{q_1q_2}{d^2}$

Where:

$k=9\cdot 10^9\ N.m^2/c^2$

q1, q2 = the particles' charge

d= The distance between the particles

Suppose the distance is reduced to d'=d/3, the new force F' is:

$\displaystyle F'=k\frac{q_1q_2}{\left(\frac{d}{3}\right)^2}$

$\displaystyle F'=k\frac{q_1q_2}{\frac{d^2}{9}}$

$\displaystyle F'=9k\frac{q_1q_2}{d^2}$

$\displaystyle F'=9F$

The force is now 9 times the original force

8 0

2 years ago