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ycow [4]
3 years ago
10

A stagehand starts sliding a large piece of stage scenery originally at rest by pulling it horizontally with a force of 176 N. W

hat is the coefficient of static friction between the stage floor and the 490 N piece of scenery? a. 0.36 c. 2.8 b. -2.8 d. -0.36
Physics
1 answer:
Step2247 [10]3 years ago
4 0

<u>Answer:</u>

Option (a)

<u>Explanation :</u>

A stage hand starts sliding a large piece of stage scenery originally at rest by pulling it horizontally with a force of 176 N.

Hence Force applied  \text { Fapplied }=176 \mathrm{N}

Force on piece of scenery \mathrm{F}_{\mathrm{g}}=490 \mathrm{N}

\Sigma \mathrm{F} \mathrm{y}=\mathrm{F} \mathrm{n}-\mathrm{Fg}=0

\mathrm{Fn}=\mathrm{Fg}

\mathrm{FS}_{\mathrm{max}}=\mathrm{F}_{\mathrm{applied}}

µk = \frac{\mathrm{Fs} \max }{\mathrm{Fn}}

=  \frac{\text { Fapplied }}{\mathrm{Fg}}

=\frac{176}{490} =0.36

coefficient of static friction is 0.36

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Maksim231197 [3]

Answer:

volt ÷ ampere

Explanation:

The mathematical form of Ohms law is given by :

V = IR

Where V is voltage

I is current

R is resistance

R=\dfrac{V}{I}

The unit of voltage is volt and that of current is ampere

Unit of resistance :

R=\dfrac{\text{volt}}{\text{ampere}}

So, volt ÷ ampere is the same as the unit of resistance. Hence, the correct option is (a).

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3 years ago
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the length of iron rod at 100 C is 300.36 cm and at 159 C is 300.54 cm.Calculate its length at 0 c and coefficient of linear exp
Ugo [173]

Answer:

The length at 0 °C is 300.05 cm

Coefficient of linear expansion of iron is 1.02×10¯⁵ C¯¹

Explanation:

From the question given above, the following data were obtained:

Length (L₁) at 100 °C = 300.36 cm

Temperature 1 (θ₁) = 100 °C

Length (L₂) at 159 °C = 300.54 cm

Temperature 2 (θ₂) = 159 °C

Length (L₀) at 0 °C =?

Coefficient of linear expansion (α) =?

L₁ = L₀ (1 + θ₁α)

300.36 = L₀ (1 + 100α) ....(1)

L₂ = L₀ (1 + θ₂α)

300.54 = L₀ (1 + 159α) ..... (2)

Divide equation (2) by (1)

300.54 / 300.36 = L₀ (1 + 159α) / L₀ (1 + 100α)

1.0006 = (1 + 159α) / (1 + 100α)

Cross multiply

1.0006 (1 + 100α) = (1 + 159α)

1.0006 + 100.06α = 1 + 159α

Collect like terms

1.0006 – 1 = 159α – 100.06α

0.0006 = 58.94α

Divide both side by 58.94

α = 0.0006 / 58.94

α = 1.02×10¯⁵ C¯¹

Substitute the value of α into anything of the equation to obtain L₀. Here we shall use equation (2).

300.54 = L₀ (1 + 159α)

α = 1.02×10¯⁵ C¯¹

300.54 = L₀ (1 + 159 ×1.02×10¯⁵)

300.54 = L₀ (1 + 0.0016218)

300.54 = L₀ (1.0016218)

Divide both side by 1.0016

L₀ = 300.54 / 1.0016

L₀ = 300.05 cm

Summary:

The length at 0 °C is 300.05 cm

Coefficient of linear expansion of iron is 1.02×10¯⁵ C¯¹

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