Answer:
The frequency of the coil is 7.07 Hz
Explanation:
Given;
number of turns of the coil, 200 turn
cross sectional area of the coil, A = 300 cm² = 0.03 m²
magnitude of the magnetic field, B = 30 mT = 0.03 T
Maximum value of the induced emf, E = 8 V
The maximum induced emf in the coil is given by;
E = NBAω
Where;
ω is angular frequency = 2πf
E = NBA(2πf)
f = E / 2πNBA
f = (8) / (2π x 200 x 0.03 x 0.03)
f = 7.07 Hz
Therefore, the frequency of the coil is 7.07 Hz
What is that supposed to mean?
Answer:
14.8 m
Explanation:
S= ut + 
a
where u = initial velocity
S= (0 
)(2
) + (7.4
)(2
)
S= (7.4)(2)
S=14.8 m
Answer:
Explanation:
Distance between plates d = 2 x 10⁻³m
Potential diff applied = 5 x 10³ V
Electric field = Potential diff applied / d
= 5 x 10³ / 2 x 10⁻³
= 2.5 x 10⁶ V/m
This is less than breakdown strength for air 3.0×10⁶ V/m
b ) Let the plates be at a separation of d .so
5 x 10³ / d = 3.0×10⁶ ( break down voltage )
d = 5 x 10³ / 3.0×10⁶
= 1.67 x 10⁻³ m
= 1.67 mm.
Answer: 166.67km/hr
Explanation:
Given the following :
Distance traveled = 250km
Time taken = 1.5 hours
Recall :
Speed = Distance traveled / time taken
Speed = 250 km / 1.5 hours
Speed = 166. 67 km/hr
Speed in m/s:
166.67km/hr = (166.67 × 1000)m / 3600 s
= 166670m / 3600s
= 46.3m/s
