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ArbitrLikvidat [17]

3 years ago

10

Plz help need answer ASAP thanks

1 answer:

MAVERICK [17]3 years ago

3 0

It’s procedural memory Bc idk but procedural is how to do something and declarative is remembering something

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The distance between earth and moon is almost 384,400 km the distance can be written in scientific notation as a x 10b km where

UNO [17]

384,400 in scientific notation can be written as 3.844×10^5

3 0

4 years ago

Encoding information occurs throughout?

alexandr402 [8]

Encoding information occurs throughout forming memory and is the first step of the memory process.

8 0

4 years ago

A cannon ball is shot horizontally off a 37.0 m cliff and lands a distance of 18.5 m

4vir4ik [10]

Answer:

vₓ = 6.73 m/s

Explanation:

Assuming no other external influences than gravity, in the horizontal direction (which we make to coincide with the x- axis) , speed is constant, so, applying the definition of average velocity, we can write the following equation:

$v_{x} = \frac{\Delta x}{\Delta t} (1)$

Now, in the vertical direction (coincident with the y- axis) , as both movements are independent each other, initial velocity is zero, so we can write the following equation for the vertical displacement:

$\Delta h = \frac{1}{2} * g * t^{2} (2)$

where Δh = -37.0 m , g = -9.8 m/s2
Solving (2) for t, we get:

$t = \sqrt{\frac{2*\Delta h}{g} } =\sqrt{\frac{2*37.0m}{9.8m/s2}} = 2.75 s (3)$

Taking t₀ = 0, ⇒ Δt = t
Replacing (3) in (1), we get:

$v_{x} = \frac{\Delta x}{\Delta t} = \frac{x}{t} = \frac{18.5m}{2.75s} = 6.73 m/s$

As the horizontal velocity is constant, the initial horizontal velocity is just the average one, i.e., 6.73 m/s.

5 0

3 years ago

Harlamova29_29 [7]

Answer: check the link

hope it helps

Explanation:

3 0

3 years ago

Read 2 more answers

A solution containing 10.0 g of an unknown liquid and 90.0 g water has a freezing point of -3.33 °C. Given Kf = 1.86 °C/m for wa

Fantom [35]

Answer:

62.06 g/mol

Explanation:

We are given that a solution containing 10 g of an unknown liquid and 90 g

Given mass of solute = $W_B$ =10 g

Given mass of solvent= $W_A$ =90 g

$k_f=1.86^{\circ}C/m$

Freezing point of solution =-3.33 $^{\circ}$ C

Freezing point of solvent = $0^{\circ}$ C

Change in freezing point =Depression in freezing point

=Freezing point of solvent - freezing point of solution=0+3.33= $3.33^{\circ}$

$\Delta T_f=\frac{W_B\times K_f\times 1000}{W_A\times M_B}$

$M_B=\frac{10\times 1.86\times 1000}{3.33\times 90}$

$M_B=62.06 g/mol$

Hence, molar mass of unknown liquid is 62.06g/mol.

6 0

3 years ago

Read 2 more answers