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pishuonlain [190]
3 years ago
12

A researcher studying the nutritional value of a new candy places a 4.70g sample of the candy inside a bomb calorimeter and comb

usts it in excess oxygen.The observed temperature increase is 2.46 C . If the heat capacity of the calorimeter is 40.50kJ•K-1, how many nutritional Calories are there per gram of the candy
Chemistry
1 answer:
Luba_88 [7]3 years ago
3 0

Answer:

Calories of candy = 5.1  kcal /g

Explanation:

Given data:

Mass of candy = 4.70 g

Change in temperature = 2.46 °C

Specific heat capacity of calorimeter = 40.50 Kj/°C

Calories present per gram = ?

Solution:

Formula

Cal of candy  = specific heat capacity × change in temperature / mass

C = c . ΔT/m

C = 40.50 Kj/°C × 2.46 °C / 4.70 g

C = 99.63 kj /4.70 g

C = 21.2 kj/ g

C =  21.2 kj/ g × 0.239 kcal/kj

C = 5.1  kcal /g

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True or False: A heterozygous genotype produces the dominant phenotype because the dominant allele masks the recessive allele.
jasenka [17]
This is true! Heterozygous would be Dd, and the dominant masks the recessive
4 0
3 years ago
When 21.45 g of KNO3 was dissolved in water in a calorimeter, the temperature fell from 25.00°C to 14.14 °C. If the heat capacit
pashok25 [27]

25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)

<h3>Explanation</h3>

The process:

\text{KNO}_3\;(s) \to \text{KNO}_3\;(aq).

How many moles of this process?

Relative atomic mass from a modern periodic table:

  • K: 39.098;
  • N: 14.007;
  • O: 15.999.

Molar mass of \text{KNO}_3:

M(\text{KNO}_3) = 39.098 + 14.007 + 3\times 15.999 = 101.102\;\text{g}\cdot\text{mol}^{-1}.

Number of moles of the process = Number of moles of \text{KNO}_3 dissolved:

\displaystyle n = \frac{m}{M} = \frac{21.45}{101.102} = 0.212162\;\text{mol}.

What's the enthalpy change of this process?

Q = C\cdot \Delta T = 0.505 \times (25.00 - 14.14) = 5.4843\;\text{kJ} for 0.212162\;\text{mol}. By convention, the enthalpy change \Delta H measures the energy change for each mole of a process.

\displaystyle \Delta H = \frac{Q}{n} = \frac{5.4843\text{kJ}}{0.212162\;\text{mol}} = 25.8\;\text{kJ}\cdot\text{mol}^{-1}.

The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

4 0
3 years ago
B. if 6.73 g of na2co3 is dissolved in enough water to make 250. ml of solution, what is the molar concentration of sodium carbo
BARSIC [14]

Answer:- [Na_2CO_3]=0.254M , [Na^+]=0.508 M , [CO_3^2^-]=0.254M

Solution:- We are asked to calculate the molarity of sodium carbonate solution as well as the sodium and carbonate ions.

Molarity is moles of solute per liter of solution. We have been given with 6.73 grams of sodium carbonate and the volume of solution is 250.mL.  Grams are converted to moles and mL are converted to L and finally the moles are divided by liters to get the molarity of sodium carbonate.

Molar mass of sodium carbonate is 105.99 gram per mol. The calculations for the molarity of sodium carbonate are shown below:

\frac{6.73gNa_2CO_3}{250.mL}(\frac{1mol}{105.99g})(\frac{1000mL}{1L})

= 0.254MNa_2CO_3

So, molarity of sodium carbonate solution is 0.254 M.

sodium carbonate dissociate to give the ions as:

Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^2^-

There is 1:2 mol ratio between sodium carbonate and sodium ion. So, the molarity of sodium ion will be two times of sodium carbonate molarity.

[Na^+]=2(0.254M) = 0.508 M

There is 1:1 mol ratio between sodium carbonate and carbonate ion. So, the molarity of carbonate ion will be equal to the molarity of sodium carbonate.

[CO_3^2^-]=0.254M


5 0
4 years ago
What is the major ion in seawater?
Dmitrij [34]

Answer:

It should be chloride I am almost positive

Explanation:

Typical Seawater

Chloride (Cl-) 18.980

Sodium (Na+) 10.556

Sulfate (SO42-) 2.649

Magnesium (Mg2+) 1.262

4 0
3 years ago
Which describes a precipitate in a chemical reaction?
nekit [7.7K]

Answer:

D

Explanation: A precipitation reaction is a type of chemical reaction in which two soluble salts in aqueous solution combine and one of the products is an insoluble salt called a precipitate.

5 0
3 years ago
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