Graph would be the answer.
I hope this helps. :)
Answer:
Percent ionic character of HI bond is 4.91%.
Explanation:
<h3>
Given Data:</h3>
Measured Dipole = 0.380D
bond distance = d = 161pm = 1.61*10^-8 cm
<h3>
Calculation:</h3>
% ionic character is determined by following equation:
% ionic= (dipole measured/dipole calculated)*100
Now,
(In above step 3*10^8 is multiplied to convert coulomb into esu)
As,
So,
Now we can % ionic character using above equation:
%ionic=(0.380D/7.728D)*100
% ionic character=4.91%
Add all weighs together
calculate carbons weigh
(carb weigh/total)×100
Tin to Fluorine mass ratios:
1) For compound A:
38.5/12.3
= 3.13
2) For compound B:
56.5/36.2
= 1.56
The lowest whole number mass ratio is 2. It cannot be 1 because it is less than that required for compound B.
When 1-bromo propane is reacted with sodium metal, the propane and sodium bromide are formed.
- Propane and sodium bromide are produced when the 1-bromo propane is reacted with sodium metal.
- The Bromine which is present in the 2-bromopropane is removed through hydrogenation and combines with the sodium metal which results in the production of propane and sodium bromide.
- So we can conclude that propane and sodium bromide are produced when the 1-bromo propane is reacted with sodium metal.
Learn more about 1-bromo propane here: brainly.com/question/25597694
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