Answer:
V₂ = 918.1 cm³
Explanation:
Given data:
Initial volume = 640 cm³
Initial temperature = 100°C (100+273 = 373 K)
Initial pressure = 1490 mmHg (1490 /760 = 1.96 atm)
Final volume = ?
Final temperature = 273 K
Final pressure = 1 atm
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
now we will put the values in formula.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.96 atm × 640 cm³ × 273 K / 373 K × 1 atm
V₂ = 342451.2 atm .cm³ . K / 373 K. atm
V₂ = 918.1 cm³
Answer:
a) the final kilocalories per gram for food will be less because the mass was reduced
b)the final kilocalories per gram for food will be less since
c) the final kilocalories per gram for food will be less since the reaction will eventually go to completion
d) the final kilocalories per gram for food will be more.
Explanation:
a) the final kilocalories per gram for food will be less because the mass was reduced from 110.3 to 101.3g
b)the final kilocalories per gram for food will be less since some marshmallow fell off before the reaction
c) the final kilocalories per gram for food will be less since the reaction will eventually go to completion
d) the final kilocalories per gram for food will be more since the thermometer that got stuck will add to the value of final kilocalories per gram
The answer is 0.18
Because the equation for finding the molarity of a solution is:
Moles divided by Liter of solution,
so, you dissolve 0.32 mol of KCL in 1759 ml of Water 1759 ml is 1.759 liters when you plug the numbers in you get 0.18
Hope this helps,
kwrob
From the calculation, the pH of the solution is 4.85.
<h3>What is the pH?</h3>
The pH is defined as the hydrogen ion concentration of the solution. We have the ICE table as;
HA + H2O ⇔ H3O^+ + A^-
I 0.335 0 0
C -x +x +x
E 0.335 - x x x
Ka = 1 * 10^-14/Kb
Ka = 1 * 10^-14/1.8 × 10^–5
Ka = 5.56 * 10^-10
Ka = [H3O^+] [A^-]/[HA]
But [H3O^+] = [A^-] = x
5.56 * 10^-10 = x^2/ 0.335 - x
5.56 * 10^-10(0.335 - x ) = x^2
1.86 * 10^-10 - 5.56 * 10^-10x = x^2
x^2 + 5.56 * 10^-10x - 1.86 * 10^-10 = 0
x=0.000014 M
Now;
pH = -log 0.000014 M
pH = 4.85
Learn more about pH:brainly.com/question/15289741
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