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Yuliya22 [10]
4 years ago
5

Based on its position on the periodic table, Na is a __ at room temperature.

Chemistry
2 answers:
Eduardwww [97]4 years ago
5 0

Answer:

Solid.

Explanation:

It is in a metal group  ( on the Left Side of the Periodic Table.

Crank4 years ago
3 0

Answer: metal

Explanation:

it falls under the blue part of the periodic table and according to the key it is a metal. i also took two years of AP chem so i have a little experience with the subject ;) hope this helps!!!

good luck!!!! <3

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Argon, Ar, is a noble gas. How many miles of argon are in 200 gram sample of argon.? (Answer rounded to the ones place)
tatuchka [14]

The answer is 39.948 g/mol so rounded to the nearest ones would be 40.00 g/mol.

3 0
3 years ago
How many grams are in 36.2 moles of Iron (I) fluoride?
Allushta [10]

Answer:

4084.808 grams (SigFigs: 4085 grams)

Explanation:

The molar mass of Iron fluoride is 112.84 g/mol.

To calculate the mass, multiply the molar mass by the number of moles.

36.2 mol * 112.84 g/mol = 4084.808 g

Convert to Sigfigs (if necessary):

4085 g

5 0
3 years ago
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What are the main functions of the human skeletal system?
laiz [17]

Answer:

The answer is A.........

3 0
3 years ago
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Calculate the number of molecules in 9.00 moles H2S.
Alex Ar [27]
1 mole of any substance is: 6.022*10²³ atoms or molecules.
9 moles of H₂S=9(6.022*10²³ molecules)=5.4198*10²⁴ molecules.

answer:there are 5.4198*10²⁴ molecules in 9.00 moles of H₂S. 


3 0
4 years ago
Read 2 more answers
A certain compound has the following percent composition: 57.1% C, 4.8% H, and 38.l% O.
crimeas [40]

Answer:

C₆H₆O₃

Explanation:

Calculation sequence:

% => grams => moles => reduce => empirical Ratio

Molecular multiple = Molecular Mass / Empirical Mass

  C: => 57.1% => 57.1 g => 57.1/12 = 4.7583

  H: =>  4.8% =>  4.8 g =>   4.8/1  = 4.8000

  O: => <u>38.1% => 38.1 g </u>=> 38.1/16 = 2.3813

TTL => 100%       100 g

Reduced Mole values =>

C : H : O => 4.7583/2.3813 : 4.8000/2.3813 : 2.3813/2.3813 => 2 : 2 :  1

∴ empirical formula => C₂H₂O

empirical formula weight => 2C + 2H + 1O = [2(12) + 2(1) + 1(16)] amu = 42 amu

molecular formula weight (given in problem) = 126 g/mole

The molecular formula is a whole number multiple of the empirical formula.

molecular multiple = 126 amu / 42 amu = 3

∴ molecular formula => (C₂H₂O)₃ => C₆H₆O₃

8 0
3 years ago
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