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aksik [14]
3 years ago
14

An atom of radon gas emits an alpha particle as shown below. Radon-222 has 86 protons and 136 neutrons. What daughter product wi

ll form from this decay? Francium-222 (87 protons) Polonium-218 (84 protons) Radium-226 (88 protons) Lead-220 (82 protons)
Chemistry
2 answers:
Ksju [112]3 years ago
6 0

Answer is Polonium-218 (84 protons).

alpha decay is an emission of ₂⁴He nucleus. If an element undergoes an alpha decay, the mass of the daughter nucleus formed is reduced by 4 compared to mass of parent atom and atomic number is reduced by 2 compared to atomic number of parent atom.

Since the parent atom has 86 protons, atomic number is 86. Hence, the daughter atom should have 86 - 2 = 84 as atomic number. The parent atom has 222 as its mass. Hence, formed daughter atom should have 222 - 4 = 218 as its mass number.

The reaction for this decay is;

₈₆²²²Rn → ₈₄²¹⁸Po + ₂⁴∝

Sidana [21]3 years ago
5 0
The answer is <span>Polonium-218 (84 protons).

Alpha particles consist of two protons and two neutrons. So, mass is 4 (2+2) amu </span>_{2}^{4}   \alpha<span>.
</span><span>When an atom of emits an alpha particle, its atomic number will be reduced by 2 and a mass number will be reduced by 4:
</span>_{Z} ^{A} X → _{Z-2} ^{Y-4} Y + _{2}^{4} \alpha<span>.</span><span>

After emission of the alpha particle from Radon-222 with 86 protons, the daughter product will have the atomic number reduced by 2: 86-2 = 84 and the mass number reduced by 4: 222-4=218:
 </span>_{86}  ^{222} Rn → _{84} ^{218} Po + _{2}^{4} \alpha.<span>


</span>
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