Cacl2 dissolve in water according to the following equation
Cacl2 + H2O = Ca(OH) + Hcl Volume= moles/molarity The reacting ratio between CaCl2 to Ca(OH) is 1:1 therefore moles of solution is also 0.0262 moles hence volume is = 0.0262mol/ 0.52mol/l = 0.0504L or50.4ml
A buffer system can be made by mixing a soluble compound that contains the conjugate ... 10.0 grams of sodium acetate in 200.0 mL of 1.00 M acetic acid.