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guajiro [1.7K]
3 years ago
10

The permanent electric dipole moment of the water molecule 1H2O2 is 6.2 * 10-30 C m. What is the maximum possible torque on a wa

ter molecule in a 5.0 * 108 N/C electric field?
Chemistry
1 answer:
stellarik [79]3 years ago
7 0

Answer:

3.1 x 10⁻²¹ Nm

Explanation:  

When placed in an external electric filed, an electric dipole experiences a torque. and this torque is represented mathematically with the equation:

torque (τ) = dipole moment vector (P) x electric field vector (E)

τ = P. E . sin θ

where θ is the angle between the water molecule and the electric field, which in this case is 90° (because this is where the torque is maximum)

τ = 6.2x10⁻³⁰Cm . 5.0x10⁸ N/C . sin90

τ = 6.2x10⁻³⁰Cm . 5.0x10⁸ N/C . 1

solve for τ

τ = 3.1 x 10⁻²¹ Nm

the maximum possible torque on the water molecule is therefore 3.1 x 10⁻²¹ Nm

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Answer:

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\frac{P_s}{Pi}= x_i

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Or in Polish…

Kwasy karboksylowe to homologiczna seria, w której związki zawierają grupę funkcyjną zwaną grupą karboksylową (-COOH). Ogólny wzór cząsteczkowy dla kwasów karboksylowych to CnH2n + 1COOH. Kwasy karboksylowe zawierają co najmniej jedną grupę karboksylową.

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