A 4.00-gram sample of sodium chloride was added to a beaker containing 40.0 mL 0.033 M lead(II)

Magnesium reacts with hydrochloric acid (HCl) as follows. Mg(s) + 2HCl(aq) -->MgCl(2)+H(2)(g) How many milliliters of hydroge

max2010maxim [7]

We are given the number of moles of solid magnesium supplied for the reaction which is 0.02 moles while hydrochloric acid is supplied in excess thus we can say that the reaction proceeds to completion. Calculation is as follows:

0.020 mol Mg ( 1 mol H2 / 1 mol Mg ) = 0.020 mol H2 gas is produced

To convert the number of moles to volume, we use the conditions at STP of 1 mol of a substance is equal to 22.4 L. Thus,

0.020 mol H2 (22.4 L / 1 mol) (1000 mL / 1 L) = 448 mL

5 0

3 years ago

The Xs show the location of beanbags a student tossed at a target. The

Nitella [24]

Answer:

D

Explanation:

3 0

3 years ago

Read 2 more answers

The reaction can be described using the equation: 2C2H25O24CO22H2O. How much C2H2is needed to react with 68.1 g of O2to produce

Sophie [7]

Answer:

22.13g

Explanation:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Next, we'll calculate the mass of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H2 = (12x2) + (2x1)

= 24 + 2 = 26g/mol

Mass of C2H2 that reacted from the balanced equation = 2 x 26 = 52g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 5 x 32 = 160g

Now, we can obtain the mass of C2H2 that will react with 68.1g of O2 as follow:

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Therefore, Xg of C2H2 will react with 68.1g of O2 i.e

Xg of C2H2 = (52x68.1)/160

Xg of C2H2 = 22.13g

Therefore, 22.13g of C2H2 is needed to react with 68.1g of O2

8 0

3 years ago

In an experiment, two unknown compounds (one an alcohol and the other an ether) of equal molecular mass were dissolved in water.

-BARSIC- [3]

Answer: B. It is an ether because it is unable to to form a hydrogen bond, so it is less soluble than water

Explanation: Alcohols $(ROH)$ are more soluble in water as they can form hydrogen bonding with water whereas ethers $(ROR)$ are less soluble as they do not form hydrogen bonds with water.

For formation of hydrogen bond, the electronegative atom (F, Oand N) must be attached to hydrogen and in ethers (ROR), there is no hydrogen directly attached to electronegative oxygen atom, thus are less soluble in water.

4 0

3 years ago

If starch, glucose and NaCl are soaked in the dialysis tubing , will there be a difference between the beginning and after 15min

spin [16.1K]

<span>Yes. If you put solutions containing the same concentration table salt, glucose and starch in different bags and place the bags in water (i.e., 0M) solution, then the bag with salt will contain more water after 15 minutes than the bag with glucose, which will contain more than the bag with starch.</span>

6 0

3 years ago