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Delvig [45]
2 years ago
11

A rotameter calibration curve (flow rate versus float position) obtained using a liquid is mistakenly used to measure a gas flow

rate. Would you expect the gas rate determined in this manner to be too high or too low?
Chemistry
1 answer:
Veronika [31]2 years ago
5 0

Answer:

I would expect the gas rate determined in this manner to be too low

Explanation:

A Rotameter can be designed to respond to the sensitivity of density, velocity, to measure the flow rate of liquid or gas enclosed in a tube. Liquids are denser than gas, and since the gas rate to be determined needed to respond to the velocity head alone of the rotameter so as to bring the forces in the tube equilibrium. Knowing if there is no flow, then the float would remain at the bottom, so gas has to flow at a higher rate compared to the liquid so the float would be in a similar position making it easier to measure the flowrate. This leaves the gas rate to be determined too low.

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Italian dressing contains olive oil and vinegar, which will separate out from each other if left to sit. This makes the dressing
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Italian salad dressing would be a suspension
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You are given 24.3 grams of Mg and combine it with 32.1 grams of Sulfur, what is the mass of MgS? *
koban [17]

Answer:

ExplanatioFirst let us compute for the molar mass of Mg(OH)2.

molar mass = 24.3 + 2 (16) + 2(1.0)

molar mass = 58.3 g/mol

 

So the mass is then:

mass = 3.2 mol * (58.3 g/mol)

mass = 186.56 gramsn:

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2 years ago
In the compound h2s hydrogen has an oxidation number of 1+ and sulfur has an oxidation number of
elena-14-01-66 [18.8K]
Oxidation number is defined as the total number of electrons that are gained or lost by the atom to form a chemical bond. 
the oxidation number of the compound H₂S is 0.
the sum of the oxidation numbers of the individual elements should add up to the oxidation number of the compound. 

(oxidation number of H x 2 H ions) + oxidation number of S = 0
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2 + x = 0
x = -2
oxidation number of S is -2
3 0
3 years ago
Read 2 more answers
What mass of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.
iren [92.7K]

91.4 grams

91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

C = mol/volume

2.45M=mol/0.5L

2.45M⋅0.5L = mol

mol = 1.225

Convert no. of moles to grams using the atomic mass of K + Cl

1.225mol * \frac{39.1+35.5}{mol}

mol=1.225

=1.225 mol . \frac{74.6g}{mol}

=1.225 . 74.6

=91.4g

therefore, 91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

What is 1 molar solution?

In order to create a 1 molar (M) solution, 1.0 Gram Molecular Weight of the chemical must be dissolved in 1 liter of water.

58.44 g make up a 1M solution of NaCl.

To learn more about molar solution visit:

brainly.com/question/10053901

#SPJ4

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How does Perth’s water cycle work?
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