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Novosadov [1.4K]
4 years ago
10

choose a substance you're familiar with. what are its physical and chemical properties? How would you measure its density? What

are some physical and chemical changes it can undergo?
Physics
2 answers:
Artist 52 [7]4 years ago
7 0
You can look at magnesium, it can react with oxygen to form oxides. (chemical) it is malleable and a solid at room temperature. (physical)

to measure its density, the mass and volume can be worked out and from this density too. look up the equation, it is quite easy :) 

physical changes -- it can be melted, and oxidized <span />
yan [13]4 years ago
3 0

Answer:

Let the substance is H_2O

1. Physical property is defined as the property of a substance which becomes evident during physical changes. Example: Melting point  of water is 0^0C

Chemical property is defined as the property of a substance which becomes evident during chemical changes. Example: Reaction of water with active metals such as sodium

2. Density is measured as the ratio of amount of mass per unit volume.

density=\frac{mass}{volume}

3.  A chemical change is defined as a change in which a change in chemical composition takes place. A new substance is formed in these reactions.

2H_2O\rightarrow 2H_2+O_2

A physical change is defined as a change in which there is alteration in shape, size etc. No new substance gets formed in these reactions.

Example: evaporation of water

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polarization

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How do convection cells in Earth's atmosphere cause high and low pressure belts?
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4 years ago
Suppose a small quantity of radon gas, which has a half-life of 3.8 days, is accidentally released into the air in a laboratory.
Daniel [21]

Answer:

1 day

Explanation:

Let the safe level = x

The current level = x + 0.2x = 1.2 x

Thus,

Half life = 3.8 days

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{3.8}\ days^{-1}

The rate constant, k = 0.1824 days⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

So,

\frac {[A_t]}{[A_0]} = x / 1.2 x = 0.8333

t = ?

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.8333=e^{-0.1824\times t}

t ≅ 1 day

<u>Lab must be vacated in 1 day.</u>

4 0
3 years ago
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