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tester [92]
3 years ago
12

If you walk at 0.7 m/s, how long would it take to walk a mile which is 1609 m

Physics
2 answers:
inessss [21]3 years ago
8 0

Answer:

\huge\boxed{\sf t = 2298.57\ secs}

Explanation:

<u>Given:</u>

Speed = v = 0.7 m/s

Distance = S = 1 mile = 1609 metre

<u>Required:</u>

Time = t = ?

<u>Formula :</u>

v = S/t

<u>Solution:</u>

v = S/t

t = S/v

t = 1609 / 0.7

t = 2298.57 secs

12345 [234]3 years ago
4 0

Answer:

\Huge \boxed{\mathrm{2298.57 \ seconds}}

\rule[225]{225}{2}

Explanation:

\displaystyle \sf Speed = \frac{Distance \ covered  }{Time \ taken}

\displaystyle \sf s = \frac{d  }{t}

The speed is 0.7 m/s.

The distance covered is 1609 m.

\displaystyle \sf 0.7 = \frac{1609  }{t}

Multiplying both sides by <em>t</em>.

Then dividing both sides by 0.7.

\displaystyle \sf t = \frac{1609  }{0.7}

\sf t= 2298.57

It would take 2298.57 seconds.

\rule[225]{225}{2}

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Hoochie [10]

Answer:

Given:

mass of the ball m = 0.144 kg

velocity v = 38 m/s

now,  change in momentum

P = m v- ( - mv)

  = 2 mv

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  = 10.944 kg-m/s

Impulse J= F. Δt

change in momentum is equal to impulse

J = 10.944 kg-m/s

we know force is equal to change in momentum per unit time

F = \dfrac{P}{t}

F = \dfrac{10.944}{0.8\times 10^{-3}}

F = 13.68 x 10³ N

F = 13.68 kN

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3 years ago
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6 0
3 years ago
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A deuteron particle consists of one proton and one neutron and has a mass of 3.34x10^-27 kg. A deuteron particle moving horizont
nikklg [1K]

_dThe radius of curvature of a subatomic particle under a magnetic field is given by the following formula:

r=\frac{mv}{qB}

Where:

\begin{gathered} r=\text{ radius} \\ v=\text{ velocity} \\ q=\text{ charge} \\ B=\text{ magnetic field} \end{gathered}

We can determine the quotient between the velocity and the charge of the deuteron particle from the formula. First, we divide both sides by the mass:

\frac{r_d}{m_d}=\frac{v}{q_B_}

Now, we multiply both sides by the magnetic field "B":

\frac{Br_d}{m_d}=\frac{v}{q}

Since the charge of the deuterion is the same as the charge of the proton and the velocity we are considering are the same this means that the quotient between velocity and charge is the same for both particles. Therefore, we can apply the formula for the radius again, this time for the proton:

r_p=\frac{m_pv}{qB}

And substitute the quotient between velocity and charge:

r_p=\frac{m_p}{B}(\frac{Br_d}{m_d})

Now, we cancel out the magnetic field:

r_p=\frac{m_pr_d}{m_d}

Now, we substitute the values:

r_p=\frac{(1.67\times10^{-27}kg)(0.385m)}{(3.34\times10^{-27}kg)}

Solving the operations:

r_p=0.193m=19.3cm

Therefore, the radius is 19.3 cm.

3 0
1 year ago
What is the frequency of a wave if the speed of the wave is 7.9m/s and the wavelength is 3.1m?​
Tpy6a [65]

Answer:

<h2>2.55 Hz</h2>

Explanation:

The frequency of the wave given it's velocity and wavelength can be found by using the formula

f =  \frac{c}{ \lambda}  \\

where

c is the velocity of the wave in m/s

\lambda is the wavelength in m

From the question

c = 7.9 m/s

\lambda = 3.1 m

We have

f  = \frac{7.9}{3.1}  = 2.548387... \\

We have the final answer as

<h3>2.55 Hz</h3>

Hope this helps you

6 0
2 years ago
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GREYUIT [131]

Answer:

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Explanation:

t = Time taken

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v = Final velocity = 460 m/s

s = Displacement = 13 cm

a = Acceleration

From the equation of motion we have

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The acceleration of the bullet as it passes through the board is -392307.6923 m/s²

5 0
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