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3 years ago

The density of the Earth is greater than the density of an equal volume of water by _____.

Physics

1 answer:

defon3 years ago

5 0

Answer:

I think the second option is correct

please mark me as brainliest

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A cart of mass M = 2.40 kg can roll without friction on a level track. A light string draped over a light, frictionless pulley c

sergiy2304 [10]

Answer:

Part a)

$a_{hanger} = g - \frac{T}{m}$

Part b)

$a_{cart} = \frac{T}{M}$

Part c)

$a = \frac{mg}{M + m}$

Part d)

$a = 1.35 m/s^2$

Explanation:

Part a)

For hanger we know that it will have tension force upwards while it has downwards its weight so we will have

$mg - T = ma$

so we have

$a_{hanger} = g - \frac{T}{m}$

Part b)

now for car that is rolling on the floor the net force is given as

$F = Ma$

$T = Ma$

$a_{cart} = \frac{T}{M}$

Part c)

now we know that the cart and the hanger both are connected to each other

so they must have same acceleration

so we will have

$T = Ma$

$mg - Ma = ma$

$a = \frac{mg}{M + m}$

Part d)

now we know that

M = 2.40 kg

m = 0.50 kg

so we will have

$a = \frac{0.50(9.81)}{2.40 + 0.50}$

$a = 1.35 m/s^2$

6 0

3 years ago

How do you solve this ?<br> Why is the ans C not B ?

melomori [17]

Explanation:

Draw a free body diagram of the toolbox. There are two forces:

Weight force mg pulling down,

and applied force F pulling up.

Sum of forces in the y direction:

∑F = ma

F − mg = ma

45 N − 15 N = (3 kg) a

a = 10 m/s²

The answer should be B. It's possible the answer key has a mistake.

4 0

3 years ago

An experiment is conducted on a long straight wire of diameter d. A constant current is sent through the wire and the magnetic f

Anton [14]

Answer:

$B_2 = \frac{B_1}{2}$

Explanation:

As per Ampere's law the magnetic field at the surface of the wire is given as

$\int B. dL = \mu_0 i$

here we have

$B . (\pi d) = \mu_0 i$

so we will have

$B_1 = \frac{\mu_0 i}{\pi d}$

now again we use same value of current but wire with double the diameter

so the magnetic field at the surface is given as

$B_2 = \frac{\mu_0 i}{2\pi d}$

so we have

$B_2 = \frac{B_1}{2}$

5 0

3 years ago

9. All of the following are adaptations of herbivores EXCEPT:

postnew [5]

Answer:

B.KEEN EYESIGHT thats for predators !

Explanation:

Herbivores have multiple stomachs to process tough foods, coats to blend in so they don't get eaten, and tough teeth for chewing on the plants. THEY DO NOT HAVE PREY, THEY ARE THE PREY.

5 0

3 years ago

A town requiring 2.0 m3/s of drinking water has two sources, a local well with 15 g/m3 nitrate (as N) and a distant reservoir wi

kati45 [8]

Explanation:

Drinking water requirement in town 2.0 m^3/s of water per second

nitrate in local well nitrate per 15 $\mathrm{m}^{3}$ of water

nitrate in distant reservoir $=5 \mathrm{~g} / \mathrm{m}^{3}$

Let the flow rate of well

flow rate of reservoir $=y m^{3} / s$

Drinking water requirement is $45 \mathrm{ppm}$ or $45 \mathrm{~g} / \mathrm{m}^{3}$

therefore, the total flow of drinking water

8 0

2 years ago