<span>(a).the heat trasfer surface area and heat flux on the surface of filament are
Area of Surface= µDL=3.14(0.05cm)(5cm)= 0.785 cm square
qs=Q/Area of surface= 150W/0.785= 191W/cmsq.=1.91x10Âłx10ÂłW/Msq
(b). the heat surface on the surface of heat bulb
Area of surface = 3.14xD²= 3.14(8CM)²= 201.1cm²
qs=Q/Area of surface=150w/201.1cm²=0.75 w/cm²= 7500w/m²
the amount and cost of electrical energy consumed during one period is
Electrical Consumption=QΛt=(0.15 KW)(365X8h/yr)=438 k Wh/yr
Annual cost= 438 kWh/yr)($.08/kWh)= $ 35.04 /yr</span>
Answer:
High amplitude is equivalent to loud sounds.
Explanation:
Subcutaneous fat is the fat that lies under the skin and isn’t necessarily harmful to your health and visceral fat is the harmful unseen fat surrounding the organs.
Complete question is;
After doing some exercises on the floor, you are lying on your back with one leg pointing straight up. If you allow your leg to fall freely until it hits the floor, what is the tangential speed of your foot just before it lands? Assume the leg can be treated as a uniform rod x = 0.98 m long that pivots freely about the hip.
Answer:
Tangential speed of foot just before it lands is; v = 5.37m/s
Explanation:
Let U (potential energy) be zero on the ground.
So, initially, U = mgh
where, h = 0.98/2 = 0.49m (midpoint of the leg)
Now just before the leg hits the floor it would have kinetic energy as;
K = ½Iω²
where ω = v/r and I = ⅓mr²
So, K = ½(⅓mr²)(v/r)²
K = (1/6) × (mr²)/(v²/r²)
K = (1/6) × mv²
From principle of conservation of energy, we have;
Potential energy = Kinetic energy
Thus;
mgh = (1/6) × mv²
m will cancel out to give;
gh = (1/6)v²
Making v the subject, we have;
v = √6gh
v = √(6 × 9.81 × 0.49)
v = √28.8414
v = 5.37m/s
Answer:
0.02
Explanation:
Force,
where N is normal reaction and coefficient of kinetic friction is
. Also, N is equivalent to mg ie N=mg where m is mass of an object and g is acceleration due to gravity. Making
the subject of the formula then
![\mu_k=\frac {F}{mg}](https://tex.z-dn.net/?f=%5Cmu_k%3D%5Cfrac%20%7BF%7D%7Bmg%7D)
Substituting F with 2 N, m with 10 kg and g with 9.81 then
![\mu_k=\frac {2}{10\times 9.81}=0.0203873598369\approx 0.02](https://tex.z-dn.net/?f=%5Cmu_k%3D%5Cfrac%20%7B2%7D%7B10%5Ctimes%209.81%7D%3D0.0203873598369%5Capprox%200.02)