Answer:
g = 8.61 m/s²
Explanation:
distance of the International Space Station form earth is 200 Km
mass of the object = 1 Kg
acceleration due to gravity on earth = 9.8 m/s²
mass of earth = 5.972 x 10²⁴ Kg
acceleration due to gravity = ?
r = 6400 + 200 = 6800 Km = 6.8 x 10⁶ n
using formula


g = 8.61 m/s²
I think it false. Sorry if i'm wrong.
Answer:
Explanation:
There's a formula for this:

F being force, k being the spring constant, and displacement being the change in x
We are given the force and the spring constant, so this is essentially isolating the Δx term. Do 60N/120N per meter. The newtons cancel out and you get a final answer of Δx = 0.5 meters
Answer:
Work done = 35467.278 J
Explanation:
Given:
Height of the cone = 4m
radius (r) of the cone = 1.2m
Density of the cone = 600kg/m³
Acceleration due to gravity, g = 9.8 m/s²
Now,
The total mass of the cone (m) = Density of the cone × volume of the cone
Volume of the cone = 
thus,
volume of the cone =
= 6.03 m³
therefore, the mass of the cone = 600 Kg/m³ × 6.03 m³ = 3619.11 kg
The center of mass for the cone lies at the
times the total height
thus,
center of mass lies at, h' = 
Now, the work gone (W) against gravity is given as:
W = mgh'
W = 3619.11kg × 9.8 m/s² × 1 = 35467.278 J
The 'Rite of Spring' was composed by Igor Stravinsky.