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Vlada [557]
3 years ago
7

What is the oxidation state of an individual sulfur atom in so42−?

Chemistry
1 answer:
hichkok12 [17]3 years ago
4 0

The oxidation state of single oxygen atom is -2 since it is more electronegative and like to gain electrons.

The sum of the oxidation states of each atom = charge of compound

Let’s say the oxidation state of Sulfur is x.

Hence,

<span>      x +4 * (-2) = -2</span>

<span>      x – 8         = -2</span>

<span>                  x   = +6</span>

<span>The oxidation state of individual Sulfur atom is +6</span>

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