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3 years ago

What is the oxidation state of an individual sulfur atom in so42−?

Chemistry

1 answer:

hichkok12 [17]3 years ago

4 0

The oxidation state of single oxygen atom is -2 since it is more electronegative and like to gain electrons.

The sum of the oxidation states of each atom = charge of compound

Let’s say the oxidation state of Sulfur is x.

Hence,

x +4 * (-2) = -2

x – 8 = -2

x = +6

The oxidation state of individual Sulfur atom is +6

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4 years ago

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Answer:

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Explanation:

Hello there!

In this case, according to the definition of the Avogadro's number and the molar mass, it is possible to say that 6.022x10^{23} atoms of barium equal one mole, and at the same time, 1 mole equals 137.327 grams of this element; thus, it is possible to say that 6.022x10^{23} atoms of barium have a mass of 137.327 grams; therefore, it i possible for us to calculate the required mass in grams as shown below:

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