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Vlada [557]
3 years ago
7

What is the oxidation state of an individual sulfur atom in so42−?

Chemistry
1 answer:
hichkok12 [17]3 years ago
4 0

The oxidation state of single oxygen atom is -2 since it is more electronegative and like to gain electrons.

The sum of the oxidation states of each atom = charge of compound

Let’s say the oxidation state of Sulfur is x.

Hence,

<span>      x +4 * (-2) = -2</span>

<span>      x – 8         = -2</span>

<span>                  x   = +6</span>

<span>The oxidation state of individual Sulfur atom is +6</span>

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Read 2 more answers
A. Density of Liquids
morpeh [17]

Answer:

Mass of liquid: 20.421g

Density= 1.0109405940594 g/mL

Explanation:

Mass of liquid

To find mass of liquid you take the mass of beaker + liquid (171.223g) and subtract it from the Mass of beaker (beaker without the water). The difference is the answer.

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To find density you use the formula Mass/Volume. Take the Volume given, and the mass of the liquid you just found.

20.421mL/20.421g = 1.0109405940594 g/mL

5 0
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Marina86 [1]

Answer:

2.52 x 10^{-23} J

Explanation:

The energy given off by the microwave can be determined by the application of Planck's energy formula:

E = hf

where: E is the required energy, h is Planck's constant (6.626 x 10^{-34}m^{2}Kg/s), and f is the frequency (3.8 x 10^{10} Hz).

So that;

E = 6.626 x 10^{-34} x 3.8 x 10^{10}

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Therefore, the energy released by the wave is 2.52 x 10^{-23} J.

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3 years ago
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Answer:

This would be Conduction

Explanation:

Conduction is the transfer of heat between two surfaces in contact with each other like the bird and the eggs.

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