What is the oxidation state of an individual sulfur atom in so42−?

Chemistry

1 answer:

hichkok12 [17]3 years ago

4 0

The oxidation state of single oxygen atom is -2 since it is more electronegative and like to gain electrons.

The sum of the oxidation states of each atom = charge of compound

Let’s say the oxidation state of Sulfur is x.

Hence,

x +4 * (-2) = -2

x – 8 = -2

x = +6

The oxidation state of individual Sulfur atom is +6

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