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Kaylis [27]
3 years ago
6

What happens when nitrogen fills its valence shell?

Chemistry
2 answers:
zavuch27 [327]3 years ago
5 0

Answer:

i think its d

Explanation:

andre [41]3 years ago
3 0
I think it’s C, Three electrons are gained, creating N^-3
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Which of the following diagrams represents a single<br> replacement reaction?
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Answer:

It's a, trust me I'm very good with chemistry

3 0
2 years ago
5. Why doesn't the air at a frontal boundary mix?​
Vsevolod [243]

Answer:

At a front, the two air masses have different densities, based on temperature, and do not easily mix. One air mass is lifted above the other, creating a low pressure zone.

Explanation:

Hope this helps!

4 0
3 years ago
Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re
borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

                        A            +            B           ⇄        C

where;

numbers of moles = 0.386 mol C  (g)

Volume =  7.29 L

Molar concentration of C = \frac{0.386}{7.29}

= 0.053 M

                        A            +            B           ⇄        C

Initial               0                           0                      0.530    

Change          +x                          +x                       - x

Equilibrium      x                           x                      (0.0530 - x)

K = \frac{[C]}{[A][B]}

where

K is given as ; 78.2 atm-1.

So, we have:

78.2=\frac{[0.0530-x]}{[x][x]}

78.2= \frac{(0.0530-x)}{(x^2)}

78.2x^2= 0.0530-x

78.2x^2+x-0.0530=0  

Using quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

where; a = 78.2 ; b = 1 ; c= - 0.0530

= \frac{-b+\sqrt{b^2-4ac} }{2a}   or \frac{-b-\sqrt{b^2-4ac} }{2a}

= \frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}  or \frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}

= 0.0204  or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

     = 0.0530 - 0.0204

     = 0.0326

Total number of moles at equilibrium = 0.0204 +  0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

V = \frac{nRT}{P}

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K  (fixed constant temperature )

V (volume) = ???

V=\frac{(0.0734*0.0821*273.15)}{(1.00)}

V = 1.64604

V ≅ 1.65 L

3 0
3 years ago
The density of pentanol, C3H20, is 0.8110 g/mL. Calculate the volume occupied by 7.455 moles of pentanol. What is the volume occ
lozanna [386]

Answer:

i dont no ehh ahh i answer this question and this question is an dibitual sence

Explanation:

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mabahslambbsoalnqnmlpigfqjskbdnmxnxb slabslwobdksjwmsnmaksbkakskslanksoqlmmbsjpqloyewqasfhjllmvxxwtyipeorirubamsbsmsnsmsoandbaksnsgaks

7 0
3 years ago
A+uniform+cube+is+subjected+to+volume+expansion. +if+each+side+is+decreased+by+1%,+then+bulk+strain+is
laiz [17]

A uniform cube is subjected to volume expansion. Each side gets decreased by 1%, then the bulk strain is 0.03.

<h3>What is Volume?</h3>

Volume is the space occupied by a three-dimensional object.

<h3 />

Given that, the side cube is l, then

volume V = l³

\dfrac{\Delta V}{V} = \dfrac{3D1}{1}

For change in volume

% Change in volume = 3× % change in length

= 3 × 1%

Hence, bulk strain = 0.03.



Thus, the bulk strain is 0.03.

Learn more about bulk strain

brainly.com/question/14070556

#SPJ4



5 0
2 years ago
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