<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
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<span>I hope this helps! </span>
hello there
This is a tricky question but i think i have solved it
Account 1: $100
Account 2: $150
Account 3: $250
If my answer helped please mark me as brainliest thank you and have a great day!
Katherine earned $15 an hour, divide $105 by the seven hours she worked
Answer C. The pattern is that each number in sequence 1 is being doubled to get the number in sequence 2, and 40*2=80
To compare the numbers, go from left to right examining the numbers carefully. so look at a., 3.7 can be written as 3.700, if u look, 3 and 0, it is definetly bigger than 0.01 and 0.001
