Answer:
Frequency of p 
Frequency of p 
Number of individuals with homozygous dominant (AA) 
Number of individuals with heterozygous (Aa)
Number of individuals with homozygous recessive (aa) 
Explanation:
Out of 100 people, 10 have albino skin (aa)
So, the frequency of homozygous recessive individuals
is 
Now, q will be

As per Hardy Weinberg's equation -

Substituting the value of q in above equation, we get -

Now the frequency of homozygous dominant (AA) will be

Hence, out of 100 people
people are homozygous dominant (AA)
Like wise out of 100 people
people are homozygous recessive (aa)
As per As per Hardy Weinberg's equation-

Substituting the values in above equation, we get -

So, out of 100 people
people are heterozygous (Aa)