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Tcecarenko [31]
3 years ago
5

When jumping, a flea accelerates at an astounding 1500 m/s2 , but over only the very short distance of 0.41 mm ?

Physics
1 answer:
STatiana [176]3 years ago
4 0
<span>V² = 2*a*y = 1.17 m²/s² at 0.45 mm height

H = V²/(2g) + 0.00045 = 0.0597 + 0.00045 = 0.06014 m = 6.014 cm </span>
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Professional baseball pitchers deliver pitches that can reach the blazing speed of 100 mph (miles per hour). A local team has dr
Wittaler [7]

Answer:

A. ) K =126. 7 J

B. ) h= 91.1 m.

Explanation:

A)

  • Assuming no air resistance, once released by the pitcher, the speed must keep constant through all the trajectory, so the kinetic energy of the ball can be expressed as follows:

       K = \frac{1}{2}*m*v^{2}  =  \frac{1}{2}*0.142 kg*(42.24m/s)^{2} = 126.7 J (1)

B)

  • Neglecting air resistance, total mechanical energy must be the same at any point, so, if we choose the ground level as the zero reference level for the gravitational potential energy, and assuming that the ball attains this kinetic energy just before striking ground, this value must be equal to the gravitational potential energy just before be dropped, so we can write the following equality:

        U_{o} = K_{f} = 126. 7 J (2)

        ⇒ m*g*h = 126. 7 J

  • Solving for h, we get:

       h = \frac{K_{f}}{m*g} = \frac{126.7J}{0.1420kg*9.8m/s2} = 91.1 m (3)

4 0
3 years ago
Explain the significance of kelvin temperature scole.​
Marrrta [24]

Answer:

The Kelvin temperature scale is used by scientists because they wanted a temperature scale where zero reflects the complete absence of thermal energy. ... Many quantum mechanical properties are washed out by the thermal agitation that occurs in materials.

3 0
3 years ago
Read 2 more answers
A wave travels at a frequency of 387 Hz. What is<br>the period of the wave?<br>​
Ulleksa [173]

Answer:

¹/₃₈₇ second

Explanation:

<em>The period of a wave is the reciprocal of its frequency.</em>

So, simply, the frequency is ¹/₃₈₇ second(s), as that is the reciprocal of the frequency, 387 Hz.

5 0
4 years ago
A motorcycle stunt person leaves the jump ramp traveling at 35 m/s at 22° above the horizontal
solniwko [45]

Missing questions (found on google):

A. Draw a vector representing the velocity of the motorcycle

B. Draw the horizontal and vertical components of the vector

C. Use vector resolution to find the magnitude of each component

Solution:

A-B) I have attached a picture including both the vector and its components.

Every vector can be represented using an arrow, whose length is proportional to its magnitude, and the direction is shown by the arrow.

The velocity of the motorbike here has magnitude of 35 m/s at an angle 22^{\circ} above the horizontal, so it is represented as vector v in the picture, with

|v|=35 m/s\\\theta = 22^{\circ}

The horizontal and vertical components are also represented, obtained by projecting the vector itself along the x- and y- axis, and they are indicated with v_x, v_y, respectively.

C) 32.5 m/s, 13.1 m/s

The magnitude of each component can be found using the following equations:

v_x = v cos \theta\\v_y = v sin \theta

where

v = 35 m/s is the magnitude of the vector

\theta=22^{\circ} is the angle of the projection

Substituting into the equations, we find

v_x = (35)(cos 22)=32.5 m/s

v_y = v sin \theta = (35)(sin 22)=13.1 m/s

5 0
4 years ago
An athlete of mass 70kg runs at a velocity of 6ms5-1 calculate the kinetic energy of the athlete.​
Molodets [167]
KE=1/2 mv²
= 1/2 × 70 × (6)²
= 1260
8 0
3 years ago
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