A 1-kg mass is dropped from a third floor window. The acceleration of the mass is found to be 8 m/s2. What is the average force
of air resistance? A) 1.8 N B) 7 N C) 8 N D) 9.8 N
1 answer:
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Answer:
F = 8 N
Explanation:
The question says "The body is subjected to a force with a moment of 0.4 N × m shoulder - 5 cm. What is the magnitude of this force?
Given that,
Moment/Torque,
Distance moved, d = 5 cm = 0.05 m
We need to find the magnitude of this force. We know that, the torque acting on an object is given by :
So, the magnitude of force is equal to 8 N.
The frequency of middle C on a string is
f = 261.6 Hz.
The given linear density is
ρ = 0.02 g/cm = (0.02 x 10⁻³ kg)/(10⁻² m)
= 0.002 kg/m
The length of the string is L = 1 m.
Let T = the tension in the string (N).
The velocity of the standing wave is
In the fundamental mode, the wavelength, λ, is equal to the length, L.
That is
Because v = fλ, therefore
From given information, obtain
T = (0.002 kg/m)*(261.6 1/s)²*(1 m)²
= 136.87 N
Answer: 136.9 N (nearest tenth)
f = 261.6 Hz.
The given linear density is
ρ = 0.02 g/cm = (0.02 x 10⁻³ kg)/(10⁻² m)
= 0.002 kg/m
The length of the string is L = 1 m.
Let T = the tension in the string (N).
The velocity of the standing wave is
In the fundamental mode, the wavelength, λ, is equal to the length, L.
That is
Because v = fλ, therefore
From given information, obtain
T = (0.002 kg/m)*(261.6 1/s)²*(1 m)²
= 136.87 N
Answer: 136.9 N (nearest tenth)
Answer: 50 V
Explanation:
Given
Three capacitors are connected in parallel across 50 V battery
When capacitor are connected in parallel, net capacitance is the sum of all the values
Net capacitance
Voltage in parallel circuit is same across each capacitor. Therefore, voltage across 4.7 F capacitor is 50 V