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3 years ago

A car goes from 80 kn/h to 20 km/h in 0.5 h. What is the acceleration in km/h^2? *

Physics

1 answer:

jekas [21]3 years ago

3 0

Answer:

<h2>In physics, acceleration is defined as the rate of change of the velocity of an object with respect to time. That is A = VF - VI /T; </h2><h2></h2><h2>Where A = Acceleration </h2><h2>VF = Final velocity = 20 km </h2><h2>VI = Initial velocity = 80 km </h2><h2>T= Time = 0.5 hr </h2><h2>A = (20 - 80)/ 0.5 = - 60/.5 </h2><h2>A = - 120 Km/ hr^2 </h2><h2></h2><h2>Therefore, the acceleration of the car is -120 km/hr^2. </h2><h2> Because the value is negative, the appropriate name that describe it is deceleration.</h2><h2>I Hope this helps</h2>

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During a total lunar eclipse, where is the Moon located?

krok68 [10]

During a total lunar eclipse, the Moon located in the umbra. The answer is letter A. For a total lunar eclipse to occur, the Sun, Earth and Moon must be aligned in a straight line. The Earth’s umbra complete covers the Moon. The earth’s umbra is about 870,000 miles wide.

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3 years ago

An electric field of magnitude 2.35 V/m is oriented at an angle of 25.0° with respect to the positive z-direction. Determine the

zzz [600]

Answer:

The magnitude of the electric flux is $3.53\ N-m^2/C$

Explanation:

Given that,

Electric field = 2.35 V/m

Angle = 25.0°

Area $A= 1.65 m^2$

We need to calculate the flux

Using formula of the magnetic flux

$\phi=E\cdot A$

$\phi = EA\cos\theta$

Where,

A = area

E = electric field

Put the value into the formula

$\phi=2.35\times1.65\times\cos 25^{\circ}$

$\phi=2.35\times1.65\times0.91$

$\phi=3.53\ N-m^2/C$

Hence, The magnitude of the electric flux is $3.53\ N-m^2/C$

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3 years ago

What is the angle of refraction when a ray of light passes frm ethanol to air

77julia77 [94]

Answer: Your answer is<u> 1.36.</u>

Hope this helps!

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3 years ago

A dvd drive has a maximum speed of 72000 revolutions per minute. if a dvd has a diamter of 12 what is the linear speed

Brilliant_brown [7]

The question isn't clear enough, I think it ask us to calculate the linear speed of a point at the edge of the DVD.
Now let's imagine we're a point at the edge of the DVD, we're undergoing a circular motion. Each minute we will complete a circular track 7200 times, now we need to know the distance we travel each turn. The perimeter of the DVD, a circular object is:
$P=2\pi.R$
Know recall that:
$v=\frac{d}{t}$
We now need to know how much distance is traveled during a minute or 60 seconds:
$D=7200\times 2\pi\times R$
Finally we divide this result with t=60 seconds:
$v=\frac{7200\times2\pi\times R}{60}
\\
R=\frac{12}{2}=6
$
$v\approx 4523.89 \frac{units}{second}$
Where the distance units were named units as the length unit is not specified in this exercise.<span />

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4 years ago

A net force of 40 N south acts on an object with a mass of 20 kg. What is the object's acceleration? (Hint: Use the formula a =

Marta_Voda [28]

Answer:

2m/s2 south

Explanation:

Trust

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4 years ago