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Paha777 [63]
3 years ago
6

Scoring scheme: 3-3-2-1 using the ion concentration values in cells #3 & #5 in the expression, ecell#5 - ecell#3 = -(0.0257/

2)ln{([fe2+(cell#5)]2[fe3+(cell#3)]2)/([fe3+(cell #5)]2[fe2+(cell#3)]2)}, calculate the theoretical cell voltage difference between cells #5 and #3.
Chemistry
1 answer:
nexus9112 [7]3 years ago
3 0
I made a fake account and everything but still no answer. Brainly done got me [email protected] up
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Which of the following is not true? a. The freezing point of sea water is lower than the freezing point of pure water. b. The bo
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Answer:

The false statement is b.

The boiling point of a water sample from the Salt Lake is lower than the boiling point of pure water

Explanation:

This excersise refers to colligative properties.

Boiling point refers to the property of boiling point elevation. In a solution of ions, as water sea or water from lakes, the boiling point will be higher than water pure.

It is logical to say that, because these sort of water have ions. Remember that colligative properties depends on the solute particles.

T° boiling solution - T° pure solvent = Kb . m . i

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We have to always consider the i, which means Van't Hoff factor, number of ions dissolved in solution. As the i is higher, the freezing point of solution will be lower, and the boiling point of solution will be higher.

They are true statement a and c.

In solution of., [NaCl] = 0.1M, as it is a higher concentration, the molality is also higher than a solution of [NaCl] = 0.05.

As water sample form Salt Lake has certain ions, it is logical to say that the boiling point of this water is higher than boiling point of pure water.

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i found this the question is different but I think the situation is same

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