Answer:
A. 0.2395 w/w %
B. 2394ppm
Explanation:
A. To find concentrationin percent by mass of the solution we need to calculate mass of glycerol and mass of water. The formula is:
Mass glycerol / Total mass * 100
<em>Mass glycerol:</em>
The solution is 2.6x10⁻²moles / L. As there is 1L of solution there are 2.6x10⁻² moles of glycerol. In mass (Using molar mass glycerol: 92.09g/mol):
2.6x10⁻² moles of glycerol * (92.09g / mol) = 2.394g glycerol
<em>Mass of water:</em>
998.9mL and density = 0.9982g/mL:
998.9mL * (0.9982g/mL) = 997.1g of water.
That means percent by mass is:
% by mass: 2.394g / (997.1g + 2.394g) * 100 = 0.2395 w/w %
B. Parts per million are mg of glycerol per L of solution. As in 1L there are 2.394g. In mg:
2.394g * (1000mg / 1g) = 2394mg:
Parts per million: 2394mg / L = 2394ppm
It is the R group or the variable group that determines the chemical properties of alcohols and amines. Depending on the number of polar and non polar groups and other molecular parts.
Answer:
Kinetic energy to Electrical energy.
Explanation:
When stationary bike is pedaled the wheels of the bike rotates which is a form of kinetic energy, this kinetic energy can be converted into electricity when connected to a generator.
From _Kinetic_ energy to _Electrical_ energy.
217 ml of 0.05 M HCl will be required to react with 5 gm of MnO2 according to the equation given.
Explanation:
The balanced chemical equation is given as:
4HCl(aq) + MnO2(s) → 2H2O(l) + MnCl2(aq) + Cl2(g)
This shows that 4 moles of HCl reacts with 1 mole of MnO2
the mass of Manganese oxide is given as 5 grams
molar mass of MnO2 = 86.93 grams/mole
number of moles of MnO2 is given by
number of moles = 
number of moles= 
= 0.0575 moles of MnO2
From the equation:
4 moles of HCl reacts with 1 mole of MnO2
x moles of HCl reacts with 
moles of MnO2
=
= 0.23 moles of HCl will react
atomic mass of HCl = 36.46 Grams/mole
mass = 0.23 x 36.46
= 8.3858 grams.of HCl
molarity of HCl = 
volume is 1 litre
so molarity is 0.23 M
Using the formula
M1V1 = M2V2
0.05 x 1 = 0.23 X x
x = 0.217 litre
so 217 ml of 0.05 M HCl will be required to react with 5 gm of MnO2.
