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Tamiku [17]
2 years ago
8

The equilibrium constant for the reaction of carbon monoxide with water is 1.845. if 1.00 mol of each reactant is placed in a 2.

00 l container, what is the concentration of carbon dioxide at equilibrium? co(g) + h2o(g) co2(g) + h2(g)
Chemistry
1 answer:
SpyIntel [72]2 years ago
4 0
[CO] = 1 mol / 2L = 0.5 M

[
According to the equation:

and by using the ICE table:

             CO(g) + H2O(g) ↔   CO2(g) + H2(g)

initial     0.5            0.5                    0          0

change  -X              -X                   +X         +X
     
Equ       (0.5-X)       (0.5-X)                     X            X

when Kc = X^2 * (0.5-X)^2

by substitution:

1.845 = X^2 * (0.5-X)^2  by solving for X 

∴X = 0.26

∴ [CO2] = X = 0.26
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63.05% of MgCO3.3H2O by mass

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<em>of MgCO3.3H2O in the mixture?</em>

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0.01769 moles MgCO3.3H2O

<em>Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-</em>

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