1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elan Coil [88]
4 years ago
14

Temporary insurance cannot be purchased to cover single events like a vacation true or false

Mathematics
2 answers:
statuscvo [17]4 years ago
8 0
False is the correct answers
frosja888 [35]4 years ago
6 0

Answer:

This is false.

Step-by-step explanation:

Temporary insurance can be purchased to cover single events like a vacation. There are many types of temporary insurance like - single event public liability insurance. This type of insurance covers events like- music concerts, movie screenings, vacations etc. that in case of any accident, the liability is to be paid by the insurance company.

You might be interested in
Dana has $25, she went to the store and spent $10. She then received $50 for a birthday present. Dana was excited until she real
MissTica

Dana:

Starts with 25 = 25

Spends 10 = 25 - 10 = 15

Received 50 = 15 + 50 = 65

New tires cost 75 = 65 - 75 = -10

Tracey:

Starts with 50 = 50

Gets gas for 25 = 50 - 25 = 25

Received 100 = 25 + 125 = 125

Purchased boots for 150 = 125 - 150 = -25

Tracey ends up with the least amount of money after their purchases.

Hope this helps! :)

8 0
3 years ago
Read 2 more answers
Help plz im stuck on this​
german

Answer:

13 cm

Step-by-step explanation:

AC=BD=13 cm

8 0
3 years ago
A right cone has a slant height of 20 feet, and the diameter of the base is 24
ipn [44]

Answer:

D. 16 ft

Step-by-step explanation:

h = √20² - (24/2)² = √400-144 = √256 = 16

7 0
3 years ago
Help geometry B, the last option is 260 degrees
Leto [7]

Answer:

Q + S = 360 - 55 - 45 = 260

Q = S

=> Q = 260/2 = 130

C is correct

5 0
3 years ago
Help I’ll do anything just help
Gnom [1K]

Answer:

1) {n}^{2}  - 81 \\ (n - 9)(n + 9)

2) \:  \: {a}^{2}  - 121 \\ (a - 11)(a + 11)

3) \:  \:  {n}^{2}  - 16 \\ (n - 4)(n + 4)

4)  \:  \: 9 {x}^{2}  - 144 \\  {3}^{2}  {x}^{2}  -  {12}^{2}  \\ (3x - 12)(3x + 12)

5) \: 2 {x}^{2}  - 9 \\ (2x - 3)(x + 3)

6) \:  \: 4 {w}^{2}  - 9 \\  {2}^{2}  {w}^{2}  -  {3}^{2}  \\ (2w + 3)(2w - 3)

7) \:  \: 4 {n}^{2}  - 1 \\  {2}^{2}  {n}^{2}  -  {1}^{2}  \\ (2n  + 1)(2n - 1)

8) \:  \: 1 - 16 {x}^{2}  \\  {1}^{2}  -  {4}^{2}  {x}^{2}  \\ (1 - 4x)(1  +  4x)

9) \:  \: {x}^{2}   - {y}^{2}  \\ (x - y)(x + y)

10) \:  \: 9 -  {c}^{2}  \\  {3}^{2}  -  {c}^{2}  \\ (3 - c)(3 + c)

11) \:  \:  {n}^{2} -  25 \\  {n}^{2}  -  {5}^{2}  \\ (n + 5)(n - 5)

13)49 - 4 {a}^{2}  \\  {7}^{2}  -  {2}^{2}  {a}^{2}  \\ (7 - 2a)(7 + 2a)

14) {a}^{2}  {b}^{2}  -  {c}^{4}  \\ (ab -  {c}^{2} )(ab +  {c}^{2} )

15) \:  \: 4  {x}^{2}  {y}^{2}  - 9 {z}^{2} \\  {2}^{2}   {x}^{2}  {y}^{2}  -  {3}^{2}  {z}^{2}  \\ (2xy - 3z)(2xy + 3z)

hope this helps

sorry, I don't know how solve the 12th one.

thanks.

7 0
3 years ago
Other questions:
  • If someone used 1/4 of an ounce of nuts to make 1/12 of a recipe of cookies , how many ounces of nuts will she need to make one
    9·1 answer
  • Fraction 2 over 18 in simplest form
    8·2 answers
  • Any of these please I’m having difficulty
    9·1 answer
  • Three people each select a letter of the alphabet. What is the probability that they select the same letter?
    10·1 answer
  • 4x^2-4x=+1 by factoring ​
    5·1 answer
  • Sam took 4 courses last semester: Calculus, Biology, History, and Physics. The means and standard deviations for the final exams
    15·2 answers
  • Consider a maximization linear programming problem with extreme points xi, x2, Xz. and x4. and extreme directions d1,. d2, and d
    6·1 answer
  • Can anyone help me with this? I know that angle B is 90°
    14·1 answer
  • Solve the system of equations.<br> 2x + 2y = -16<br> y = -x -8
    12·1 answer
  • Drag and Drop the correct answer into the boxes below.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!