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Anvisha [2.4K]
2 years ago
13

Name the values Of the 4s in the number 400,440

Mathematics
1 answer:
gavmur [86]2 years ago
6 0

The first value of 4 is in the tens place.

The second value of 4 is in the hundreds place.

The third value of 4 is in the hundred thousands place

40

400

400,000

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Whats the answer to 45=x(14-x)
ElenaW [278]
45=x(14-x)\\ \\45=14x-x^2\\ \\x^2-14x+45=0\\ \\\Delta = b^{2}-4ac =  (-14)^{2}-4*1* 45=196-180=16 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{14- \sqrt{16}}{2}=\frac{14-4}{2}= \frac{12}{2}=6\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{14+\sqrt{16}}{2}=\frac{14+4}{2}= \frac{18}{2}=9
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kompoz [17]

Answer:

I think it is the 3rd one

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6 twentieth 2 eights=
Fynjy0 [20]
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Most adults would not erase all of their personal information online if they could. A software firm survey of 480 randomly selec
Westkost [7]

Answer:

-7.90

Step-by-step explanation:

Let's write the null hypothesis (H0) and alternative hypothesis (Ha) from the claim statement

P = population proportion of adults who would erase all of their personal information online if they could

H_{0}:P=0.5

H1 P< 0.5

Let's write the given information:

n = sample size = 480

sample proportion = \hat p = 0.35

formula of z test statistic for one sample proportion test is as follows:

Z=\frac{\hat p-P}{\sqrt{\frac{P\times(1-P)}{n}}}

plug the above values in the above formula we get

Z =\frac{0.35-0.5}{\sqrt{\frac{0.35(1-0.5)}{480}}}=Z=-7.85584

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3 0
3 years ago
The null hypothesis for an ANOVA is that all treatments/samples come from populations with the same mean. The alternative hypoth
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Answer:

Alternative hypothesis: "AT LEAST ONE" of the population means is different from the others

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

If we assume that we have n groups and we want to check if the population means are equal, th best way to check this it's with an ANOVA test.

The hypothesis for this case are:

Null hypothesis: \mu_{1}=\mu_{2}=\dots =\mu_{n}

Or in words:

Null hypothesis: All treatments/samples come from populations with the same mean

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=1.2,\dots ,n

Or we can say:

Alternative hypothesis: "AT LEAST ONE" of the population means is different from the others

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