Question

If an archer shoots an arrow straight upward with an initial velocity of 160

Answer 1

Answer:

maximum height of the arrow will be 408 m

Step-by-step explanation:

We have given the function of height as $h(t)=-16t^2+160t+8$

We know that first derivative of height will be velocity

So first derivative of height

$\frac{dh}{dt}=-32t+160$

$v(t)=-32t+160$

We know that at maximum height velocity will be zero

$-32t+160=0$

t = 5 sec

Sp arrow will be at maximum height at t = 5 sec

So height at t = 5 sec will be

$h(5)=-16\times 5^2+160\times 5+8=408m$

So maximum height of the arrow will be 408 m